結果
問題 | No.2768 Password Crack |
ユーザー | 👑 binap |
提出日時 | 2024-05-31 22:09:58 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 100 ms / 2,000 ms |
コード長 | 2,635 bytes |
コンパイル時間 | 4,736 ms |
コンパイル使用メモリ | 265,380 KB |
実行使用メモリ | 25,472 KB |
平均クエリ数 | 1785.17 |
最終ジャッジ日時 | 2024-05-31 22:10:08 |
合計ジャッジ時間 | 9,518 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 32 ms
25,196 KB |
testcase_01 | AC | 26 ms
24,964 KB |
testcase_02 | AC | 99 ms
24,580 KB |
testcase_03 | AC | 99 ms
25,052 KB |
testcase_04 | AC | 99 ms
25,076 KB |
testcase_05 | AC | 34 ms
24,580 KB |
testcase_06 | AC | 99 ms
24,964 KB |
testcase_07 | AC | 100 ms
24,964 KB |
testcase_08 | AC | 45 ms
25,472 KB |
testcase_09 | AC | 98 ms
25,220 KB |
testcase_10 | AC | 100 ms
24,964 KB |
testcase_11 | AC | 98 ms
24,836 KB |
testcase_12 | AC | 98 ms
24,580 KB |
testcase_13 | AC | 98 ms
24,580 KB |
testcase_14 | AC | 100 ms
24,836 KB |
testcase_15 | AC | 99 ms
24,964 KB |
testcase_16 | AC | 99 ms
24,580 KB |
testcase_17 | AC | 100 ms
24,964 KB |
testcase_18 | AC | 100 ms
25,448 KB |
testcase_19 | AC | 65 ms
24,836 KB |
testcase_20 | AC | 63 ms
24,836 KB |
testcase_21 | AC | 98 ms
25,064 KB |
testcase_22 | AC | 81 ms
24,580 KB |
testcase_23 | AC | 39 ms
25,220 KB |
testcase_24 | AC | 58 ms
24,836 KB |
testcase_25 | AC | 98 ms
25,220 KB |
testcase_26 | AC | 58 ms
25,220 KB |
testcase_27 | AC | 83 ms
25,220 KB |
testcase_28 | AC | 41 ms
24,964 KB |
testcase_29 | AC | 47 ms
25,220 KB |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef vector<int> vi; typedef vector<long long> vl; typedef vector<vector<int>> vvi; typedef vector<vector<long long>> vvl; typedef long double ld; typedef pair<int, int> P; ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} int main(){ int n; cin >> n; vector<string> v(n + 1); rep(i, n + 1){ rep(j, i) v[i].push_back('z'); } string ans; rep(i, n){ string s1 = v[i]; string s2 = v[(n - 1) - i]; vector<int> cnt(25); for(char c = 'a'; c <= 'y'; c++){ string s = s1 + c + s2; cout << '?' << ' ' << s << "\n"; cin >> cnt[c - 'a']; } int mean = 0; rep(i, 25) mean += cnt[i]; mean /= 25; char c = 'z'; rep(i, 25) if(cnt[i] != mean) c = 'a' + i; ans += c; } cout << "! " << ans << "\n"; return 0; }