結果
問題 | No.2780 The Bottle Imp |
ユーザー | イルカ |
提出日時 | 2024-06-11 11:02:09 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,105 bytes |
コンパイル時間 | 389 ms |
コンパイル使用メモリ | 82,560 KB |
実行使用メモリ | 273,076 KB |
最終ジャッジ日時 | 2024-06-11 11:02:32 |
合計ジャッジ時間 | 13,145 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 76 ms
67,584 KB |
testcase_01 | AC | 73 ms
67,456 KB |
testcase_02 | AC | 72 ms
67,712 KB |
testcase_03 | AC | 73 ms
67,456 KB |
testcase_04 | WA | - |
testcase_05 | AC | 73 ms
67,584 KB |
testcase_06 | AC | 73 ms
67,840 KB |
testcase_07 | AC | 180 ms
87,936 KB |
testcase_08 | AC | 458 ms
103,488 KB |
testcase_09 | AC | 508 ms
113,792 KB |
testcase_10 | AC | 443 ms
113,192 KB |
testcase_11 | AC | 215 ms
88,308 KB |
testcase_12 | AC | 228 ms
95,488 KB |
testcase_13 | AC | 494 ms
104,636 KB |
testcase_14 | AC | 237 ms
95,860 KB |
testcase_15 | AC | 267 ms
96,256 KB |
testcase_16 | AC | 241 ms
96,684 KB |
testcase_17 | AC | 232 ms
96,384 KB |
testcase_18 | AC | 226 ms
95,620 KB |
testcase_19 | AC | 227 ms
96,704 KB |
testcase_20 | AC | 256 ms
96,116 KB |
testcase_21 | AC | 225 ms
96,548 KB |
testcase_22 | AC | 316 ms
97,152 KB |
testcase_23 | AC | 252 ms
99,328 KB |
testcase_24 | AC | 475 ms
114,104 KB |
testcase_25 | AC | 499 ms
114,784 KB |
testcase_26 | AC | 185 ms
87,936 KB |
testcase_27 | AC | 215 ms
94,592 KB |
testcase_28 | AC | 208 ms
94,464 KB |
testcase_29 | AC | 322 ms
121,008 KB |
testcase_30 | AC | 192 ms
88,820 KB |
testcase_31 | AC | 338 ms
107,716 KB |
testcase_32 | AC | 148 ms
87,552 KB |
testcase_33 | AC | 657 ms
247,248 KB |
testcase_34 | AC | 735 ms
273,076 KB |
testcase_35 | AC | 137 ms
85,760 KB |
testcase_36 | AC | 72 ms
67,456 KB |
testcase_37 | AC | 72 ms
67,840 KB |
testcase_38 | AC | 143 ms
85,888 KB |
testcase_39 | AC | 387 ms
153,872 KB |
testcase_40 | AC | 428 ms
154,036 KB |
testcase_41 | AC | 396 ms
154,288 KB |
testcase_42 | AC | 76 ms
67,712 KB |
testcase_43 | AC | 73 ms
67,712 KB |
ソースコード
# SCC→強連結成分をノードとみなしてDFSで訪問可能判定? from collections import defaultdict #from atcoder.scc import SCCGraph ### # https://github.com/not522/ac-library-python import sys import typing class CSR: def __init__( self, n: int, edges: typing.List[typing.Tuple[int, int]]) -> None: self.start = [0] * (n + 1) self.elist = [0] * len(edges) for e in edges: self.start[e[0] + 1] += 1 for i in range(1, n + 1): self.start[i] += self.start[i - 1] counter = self.start.copy() for e in edges: self.elist[counter[e[0]]] = e[1] counter[e[0]] += 1 class SCCGraph: ''' Reference: R. Tarjan, Depth-First Search and Linear Graph Algorithms ''' def __init__(self, n: int) -> None: self._n = n self._edges: typing.List[typing.Tuple[int, int]] = [] def num_vertices(self) -> int: return self._n def add_edge(self, from_vertex: int, to_vertex: int) -> None: self._edges.append((from_vertex, to_vertex)) def scc_ids(self) -> typing.Tuple[int, typing.List[int]]: g = CSR(self._n, self._edges) now_ord = 0 group_num = 0 visited = [] low = [0] * self._n order = [-1] * self._n ids = [0] * self._n sys.setrecursionlimit(max(self._n + 1000, sys.getrecursionlimit())) def dfs(v: int) -> None: nonlocal now_ord nonlocal group_num nonlocal visited nonlocal low nonlocal order nonlocal ids low[v] = now_ord order[v] = now_ord now_ord += 1 visited.append(v) for i in range(g.start[v], g.start[v + 1]): to = g.elist[i] if order[to] == -1: dfs(to) low[v] = min(low[v], low[to]) else: low[v] = min(low[v], order[to]) if low[v] == order[v]: while True: u = visited[-1] visited.pop() order[u] = self._n ids[u] = group_num if u == v: break group_num += 1 for i in range(self._n): if order[i] == -1: dfs(i) for i in range(self._n): ids[i] = group_num - 1 - ids[i] return group_num, ids def scc(self) -> typing.List[typing.List[int]]: ids = self.scc_ids() group_num = ids[0] counts = [0] * group_num for x in ids[1]: counts[x] += 1 groups: typing.List[typing.List[int]] = [[] for _ in range(group_num)] for i in range(self._n): groups[ids[1][i]].append(i) return groups ### N = int(input()) sccgraph = SCCGraph(N) graph = defaultdict(list) for i in range(1,N+1): A = list(map(int, input().split()))[1:] for a in A: sccgraph.add_edge(i-1, a-1) graph[i-1].append(a-1) if len(graph[0])==0: print("No") exit() groups = sccgraph.scc() if 0 not in groups[0]: print("No") exit() num_groups = len(groups) node_to_group = [0] * N # 各ノードがどの強連結成分に属するかを記録する for group_index, nodes in enumerate(groups): for node in nodes: node_to_group[node] = group_index group_connections = [set() for _ in range(num_groups)] # グラフ内のノード間の接続を強連結成分間の接続に変換する for node in range(N): current_group = node_to_group[node] for neighbor in graph[node]: neighbor_group = node_to_group[neighbor] if neighbor_group == current_group: continue group_connections[current_group].add(neighbor_group) # 各強連結成分が次の強連結成分と直接接続されているかを確認する for group in range(num_groups - 1): if group + 1 not in group_connections[group]: print("No") exit() print("Yes")