結果
問題 | No.2780 The Bottle Imp |
ユーザー | イルカ |
提出日時 | 2024-06-11 11:04:02 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 648 ms / 2,000 ms |
コード長 | 4,123 bytes |
コンパイル時間 | 376 ms |
コンパイル使用メモリ | 82,176 KB |
実行使用メモリ | 273,360 KB |
最終ジャッジ日時 | 2024-06-11 11:04:30 |
合計ジャッジ時間 | 11,931 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 78 ms
67,456 KB |
testcase_01 | AC | 77 ms
67,584 KB |
testcase_02 | AC | 65 ms
67,456 KB |
testcase_03 | AC | 65 ms
67,584 KB |
testcase_04 | AC | 64 ms
67,584 KB |
testcase_05 | AC | 65 ms
67,584 KB |
testcase_06 | AC | 65 ms
67,456 KB |
testcase_07 | AC | 161 ms
87,936 KB |
testcase_08 | AC | 407 ms
103,488 KB |
testcase_09 | AC | 447 ms
113,664 KB |
testcase_10 | AC | 399 ms
113,180 KB |
testcase_11 | AC | 169 ms
88,052 KB |
testcase_12 | AC | 199 ms
95,360 KB |
testcase_13 | AC | 447 ms
104,508 KB |
testcase_14 | AC | 207 ms
95,868 KB |
testcase_15 | AC | 226 ms
95,996 KB |
testcase_16 | AC | 218 ms
96,804 KB |
testcase_17 | AC | 214 ms
96,120 KB |
testcase_18 | AC | 202 ms
95,620 KB |
testcase_19 | AC | 220 ms
96,500 KB |
testcase_20 | AC | 248 ms
96,116 KB |
testcase_21 | AC | 208 ms
96,320 KB |
testcase_22 | AC | 276 ms
97,152 KB |
testcase_23 | AC | 234 ms
99,456 KB |
testcase_24 | AC | 391 ms
113,980 KB |
testcase_25 | AC | 465 ms
114,808 KB |
testcase_26 | AC | 178 ms
87,936 KB |
testcase_27 | AC | 203 ms
94,464 KB |
testcase_28 | AC | 187 ms
94,464 KB |
testcase_29 | AC | 314 ms
120,624 KB |
testcase_30 | AC | 163 ms
88,692 KB |
testcase_31 | AC | 278 ms
107,452 KB |
testcase_32 | AC | 120 ms
87,424 KB |
testcase_33 | AC | 604 ms
247,372 KB |
testcase_34 | AC | 648 ms
273,360 KB |
testcase_35 | AC | 132 ms
85,888 KB |
testcase_36 | AC | 66 ms
67,328 KB |
testcase_37 | AC | 65 ms
67,584 KB |
testcase_38 | AC | 144 ms
85,888 KB |
testcase_39 | AC | 360 ms
153,900 KB |
testcase_40 | AC | 356 ms
154,028 KB |
testcase_41 | AC | 349 ms
153,984 KB |
testcase_42 | AC | 73 ms
67,456 KB |
testcase_43 | AC | 69 ms
67,584 KB |
ソースコード
# SCC→強連結成分をノードとみなしてDFSで訪問可能判定? from collections import defaultdict #from atcoder.scc import SCCGraph ### # https://github.com/not522/ac-library-python import sys import typing class CSR: def __init__( self, n: int, edges: typing.List[typing.Tuple[int, int]]) -> None: self.start = [0] * (n + 1) self.elist = [0] * len(edges) for e in edges: self.start[e[0] + 1] += 1 for i in range(1, n + 1): self.start[i] += self.start[i - 1] counter = self.start.copy() for e in edges: self.elist[counter[e[0]]] = e[1] counter[e[0]] += 1 class SCCGraph: ''' Reference: R. Tarjan, Depth-First Search and Linear Graph Algorithms ''' def __init__(self, n: int) -> None: self._n = n self._edges: typing.List[typing.Tuple[int, int]] = [] def num_vertices(self) -> int: return self._n def add_edge(self, from_vertex: int, to_vertex: int) -> None: self._edges.append((from_vertex, to_vertex)) def scc_ids(self) -> typing.Tuple[int, typing.List[int]]: g = CSR(self._n, self._edges) now_ord = 0 group_num = 0 visited = [] low = [0] * self._n order = [-1] * self._n ids = [0] * self._n sys.setrecursionlimit(max(self._n + 1000, sys.getrecursionlimit())) def dfs(v: int) -> None: nonlocal now_ord nonlocal group_num nonlocal visited nonlocal low nonlocal order nonlocal ids low[v] = now_ord order[v] = now_ord now_ord += 1 visited.append(v) for i in range(g.start[v], g.start[v + 1]): to = g.elist[i] if order[to] == -1: dfs(to) low[v] = min(low[v], low[to]) else: low[v] = min(low[v], order[to]) if low[v] == order[v]: while True: u = visited[-1] visited.pop() order[u] = self._n ids[u] = group_num if u == v: break group_num += 1 for i in range(self._n): if order[i] == -1: dfs(i) for i in range(self._n): ids[i] = group_num - 1 - ids[i] return group_num, ids def scc(self) -> typing.List[typing.List[int]]: ids = self.scc_ids() group_num = ids[0] counts = [0] * group_num for x in ids[1]: counts[x] += 1 groups: typing.List[typing.List[int]] = [[] for _ in range(group_num)] for i in range(self._n): groups[ids[1][i]].append(i) return groups ### N = int(input()) sccgraph = SCCGraph(N) graph = defaultdict(list) for i in range(1,N+1): A = list(map(int, input().split()))[1:] for a in A: sccgraph.add_edge(i-1, a-1) graph[i-1].append(a-1) if N!=1 and len(graph[0])==0: print("No") exit() groups = sccgraph.scc() if 0 not in groups[0]: print("No") exit() num_groups = len(groups) node_to_group = [0] * N # 各ノードがどの強連結成分に属するかを記録する for group_index, nodes in enumerate(groups): for node in nodes: node_to_group[node] = group_index group_connections = [set() for _ in range(num_groups)] # グラフ内のノード間の接続を強連結成分間の接続に変換する for node in range(N): current_group = node_to_group[node] for neighbor in graph[node]: neighbor_group = node_to_group[neighbor] if neighbor_group == current_group: continue group_connections[current_group].add(neighbor_group) # 各強連結成分が次の強連結成分と直接接続されているかを確認する for group in range(num_groups - 1): if group + 1 not in group_connections[group]: print("No") exit() print("Yes") "🐬😢"