#990869 (PyPy3) No.2665 Minimize Inversions of Deque

• 問題: No.2665 Minimize Inversions of Deque
• ユーザー: 已经死了
• 提出日時: 2024-06-26 14:30:19
• 言語: PyPy3 (7.3.15)
• 結果: WA
• 実行時間: -
• コード長: 3,665 bytes
• コンパイル時間: 158 ms
• コンパイル使用メモリ: 82,520 KB
• 実行使用メモリ: 125,464 KB
• 最終ジャッジ日時: 2024-06-26 14:30:33
• 合計ジャッジ時間: 14,729 ms
• ジャッジサーバーID （参考情報）: judge1 / judge4

入力	結果	実行時間; 実行使用メモリ
testcase_00	WA	-
testcase_01	WA	-
testcase_02	WA	-
testcase_03	WA	-
testcase_04	WA	-
testcase_05	WA	-
testcase_06	WA	-
testcase_07	WA	-
testcase_08	WA	-
testcase_09	WA	-
testcase_10	WA	-
testcase_11	WA	-
testcase_12	WA	-
testcase_13	WA	-
testcase_14	WA	-
testcase_15	WA	-
testcase_16	WA	-
testcase_17	WA	-
testcase_18	WA	-
testcase_19	WA	-
testcase_20	WA	-
testcase_21	WA	-
testcase_22	WA	-
testcase_23	WA	-
testcase_24	WA	-
testcase_25	WA	-
testcase_26	WA	-
testcase_27	WA	-
testcase_28	WA	-
testcase_29	WA	-
testcase_30	WA	-
testcase_31	WA	-
testcase_32	WA	-
testcase_33	WA	-
testcase_34	WA	-
testcase_35	AC	332 ms; 125,464 KB
testcase_36	WA	-
testcase_37	WA	-
testcase_38	WA	-
testcase_39	WA	-

ソースコード

import os,sys,random,threading
#sys.exit() 退出程序
#sys.setrecursionlimit(10**6) #调整栈空间
from random import randint,choice,shuffle
#randint(a,b)从[a,b]范围随机选择一个数
#choice(seq)seq可以是一个列表,元组或字符串,从seq中随机选取一个元素
#shuffle(x)将一个可变的序列x中的元素打乱
from copy import deepcopy
from io import BytesIO,IOBase
from types import GeneratorType
from functools import lru_cache,reduce
#reduce(op,迭代对象)
from bisect import bisect_left,bisect_right
#bisect_left(x) 大于等于x的第一个下标
#bisect_right(x) 大于x的第一个下标
from collections import Counter,defaultdict,deque
from itertools import accumulate,combinations,permutations
#accumulate(a)用a序列生成一个累积迭代器，一般list化前面放个[0]做前缀和用
#combinations(a,k)a序列选k个 组合迭代器
#permutations(a,k)a序列选k个 排列迭代器
from heapq import  heapify,heappop,heappush
#heapify将列表转为堆
from typing import Generic,Iterable,Iterator,TypeVar,Union,List
from string import ascii_lowercase,ascii_uppercase,digits
#小写字母，大写字母，十进制数字
from math import ceil,floor,sqrt,pi,factorial,gcd,log,log10,log2,inf
#ceil向上取整，floor向下取整 ，sqrt开方 ，factorial阶乘
from decimal import Decimal,getcontext
#Decimal(s) 实例化Decimal对象,一般使用字符串
#getcontext().prec=100 修改精度
from sys import stdin, stdout, setrecursionlimit
input = lambda: sys.stdin.readline().rstrip("\r\n")
MI = lambda :map(int,input().split())
li = lambda :list(MI())
ii = lambda :int(input())
mod = int(1e9 + 7) #998244353
inf = 1<<60
py = lambda :print("YES")
pn = lambda :print("NO")
DIRS = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # 右下左上
DIRS8 = [(0, 1), (1, 1), (1, 0), (1, -1), (0, -1), (-1, -1), (-1, 0),(-1, 1)]  # →↘↓↙←↖↑↗

class BIT:
    """单点修改,区间和查询"""

    __slots__ = "size", "bit", "tree"

    def __init__(self, n: int):
        self.size = n
        self.bit = n.bit_length()
        self.tree = [0]*(n+1)

    def add(self, index: int, delta: int) -> None:
        # index 必须大于0
        while index <= self.size:
            self.tree[index]+=delta
            index += index & -index

    def _query(self, index: int) -> int: 
        res = 0
        while index > 0:
            res += self.tree[index]
            index -= index & -index
        return res

    def query(self, left: int, right: int) -> int:
        return self._query(right) - self._query(left - 1)
        
    def bisectLeft(self, k: int) -> int:
        """返回第一个前缀和大于等于k的位置pos
        1 <= pos <= self.size + 1
        """
        curSum, pos = 0, 0
        for i in range(self.bit, -1, -1):
            nextPos = pos + (1 << i)
            if nextPos <= self.size and curSum + self.tree[nextPos] < k:
                pos = nextPos
                curSum += self.tree[pos]
        return pos + 1


t=ii()

for _ in range(t):
    n=ii()
    p=li()
    que=deque()
    bit=BIT(n+5)
    tot=0
    for x in p:
        if len(que)==0:
            que.append(x)
            bit.add(x,1)
        else:
            l=bit._query(x-1)
            r=bit.query(x+1,n+3)
            bit.add(x,1)
            if l<r:
                tot+=l
                que.appendleft(x)
            elif r>l:
                tot+=r
                que.append(x)
            else:
                tot+=l
                if x<que[0]:
                    que.appendleft(x)
                else:
                    que.append(x)
    res=list(que)
    print(tot)
    print(*res)