#990993 (PyPy3) No.2360 Path to Integer

• 問題: No.2360 Path to Integer
• ユーザー: 已经死了
• 提出日時: 2024-06-27 15:41:19
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 835 ms / 2,500 ms
• コード長: 5,303 bytes
• コンパイル時間: 201 ms
• コンパイル使用メモリ: 82,012 KB
• 実行使用メモリ: 191,604 KB
• 最終ジャッジ日時: 2024-06-27 15:41:29
• 合計ジャッジ時間: 9,166 ms
• ジャッジサーバーID （参考情報）: judge4 / judge1

ファイルパターン	結果
sample	AC * 2
other	AC * 15

ソースコード

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import os,sys,random,threading
#sys.exit() 退出程序
from random import randint,choice,shuffle
#randint(a,b)从[a,b]范围随机选择一个数
#choice(seq)seq可以是一个列表,元组或字符串,从seq中随机选取一个元素
#shuffle(x)将一个可变的序列x中的元素打乱
from copy import deepcopy
from io import BytesIO,IOBase
from types import GeneratorType
from functools import lru_cache,reduce
#reduce(op,迭代对象)
from bisect import bisect_left,bisect_right
#bisect_left(x) 大于等于x的第一个下标
#bisect_right(x) 大于x的第一个下标
from collections import Counter,defaultdict,deque
from itertools import accumulate,combinations,permutations
#accumulate(a)用a序列生成一个累积迭代器，一般list化前面放个[0]做前缀和用
#combinations(a,k)a序列选k个 组合迭代器
#permutations(a,k)a序列选k个 排列迭代器
from heapq import  heapify,heappop,heappush
#heapify将列表转为堆
from typing import Generic,Iterable,Iterator,TypeVar,Union,List
from string import ascii_lowercase,ascii_uppercase,digits
#小写字母，大写字母，十进制数字
from math import ceil,floor,sqrt,pi,factorial,gcd,log,log10,log2,inf
#ceil向上取整，floor向下取整 ，sqrt开方 ，factorial阶乘
from decimal import Decimal,getcontext
#Decimal(s) 实例化Decimal对象,一般使用字符串
#getcontext().prec=100 修改精度
from sys import stdin, stdout, setrecursionlimit
input = lambda: sys.stdin.readline().rstrip("\r\n")
MI = lambda :map(int,input().split())
li = lambda :list(MI())
ii = lambda :int(input())
mod = int(1e9 + 7) #998244353
inf = int(1e20)
py = lambda :print("YES")
pn = lambda :print("NO")
DIRS = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # 右下左上
DIRS8 = [(0, 1), (1, 1), (1, 0), (1, -1), (0, -1), (-1, -1), (-1, 0),(-1, 1)]  # →↘↓↙←↖↑↗
import os,sys,random,threading
#sys.exit() 退出程序
#sys.setrecursionlimit(10**6) #调整栈空间
from random import randint,choice,shuffle
#randint(a,b)从[a,b]范围随机选择一个数
#choice(seq)seq可以是一个列表,元组或字符串,从seq中随机选取一个元素
#shuffle(x)将一个可变的序列x中的元素打乱
from copy import deepcopy
from io import BytesIO,IOBase
from types import GeneratorType
from functools import lru_cache,reduce
#reduce(op,迭代对象)
from bisect import bisect_left,bisect_right
#bisect_left(x) 大于等于x的第一个下标
#bisect_right(x) 大于x的第一个下标
from collections import Counter,defaultdict,deque
from itertools import accumulate,combinations,permutations
#accumulate(a)用a序列生成一个累积迭代器，一般list化前面放个[0]做前缀和用
#combinations(a,k)a序列选k个 组合迭代器
#permutations(a,k)a序列选k个 排列迭代器
from heapq import  heapify,heappop,heappush
#heapify将列表转为堆
from typing import Generic,Iterable,Iterator,TypeVar,Union,List
from string import ascii_lowercase,ascii_uppercase,digits
#小写字母，大写字母，十进制数字
from math import ceil,floor,sqrt,pi,factorial,gcd,log,log10,log2,inf
#ceil向上取整，floor向下取整 ，sqrt开方 ，factorial阶乘
from decimal import Decimal,getcontext
#Decimal(s) 实例化Decimal对象,一般使用字符串
#getcontext().prec=100 修改精度
from sys import stdin, stdout, setrecursionlimit
input = lambda: sys.stdin.readline().rstrip("\r\n")
MI = lambda :map(int,input().split())
li = lambda :list(MI())
ii = lambda :int(input())
mod = int(1e9 + 7) #998244353
inf = 1<<60
py = lambda :print("YES")
pn = lambda :print("NO")
DIRS = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # 右下左上
DIRS8 = [(0, 1), (1, 1), (1, 0), (1, -1), (0, -1), (-1, -1), (-1, 0),(-1, 1)]  # →↘↓↙←↖↑↗
def bootstrap(f, stack=[]):   #yield
    def wrappedfunc(*args, **kwargs):
        if stack:
            return f(*args, **kwargs)
        else:
            to = f(*args, **kwargs)
            while True:
                if type(to) is GeneratorType:
                    stack.append(to)
                    to = next(to)
                else:
                    stack.pop()
                    if not stack:
                        break
                    to = stack[-1].send(to)
            return to
    return wrappedfunc
mod=998244353
n=ii()
a=[0]+li()
g=[[] for _ in range(n+1)]
for _ in range(n-1):
    u,v=li()
    g[u]+=[v]
    g[v]+=[u]
f=[0]*(n+1) #i为起点，终点落在i子树，所有路径的权值和
p=[0]*(n+1) #在i前面加一个数字1，会得到p[i]的贡献
res=[0]*(n+1)
@bootstrap
def dfs(u,fa):
    x=len(str(a[u]))
    for v in g[u]:
        if v==fa:
            continue
        yield dfs(v,u)
        f[u]=(f[u]+f[v]+p[v]*a[u])%mod
        p[u]=(p[u]+p[v]*pow(10,x,mod))%mod
    f[u]=(f[u]+a[u])%mod
    p[u]=(p[u]+pow(10,x,mod))%mod
    yield None
dfs(1,-1)
#print(f,p)
@bootstrap
def dfs2(u,fa):
    x=len(str(a[u]))
    tf=tp=0
    for v in g[u]:
        tf=(tf+f[v]+p[v]*a[u])%mod
        tp=(tp+p[v]*pow(10,x,mod))%mod
    tf=(tf+a[u])%mod
    tp=(tp+pow(10,x,mod))%mod
    res[u]=tf
    for v in g[u]:
        if v==fa:
            continue
        f[u]=(tf-f[v]-p[v]*a[u])%mod
        p[u]=(tp-p[v]*pow(10,x,mod))%mod
        yield dfs2(v,u)
    yield None
dfs2(1,-1)
#print(res)
print(sum(res)%mod)
 
 
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