結果
問題 | No.78 クジ付きアイスバー |
ユーザー | Lê Hoàng Ngô |
提出日時 | 2024-06-28 14:54:13 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 2 ms / 5,000 ms |
コード長 | 2,783 bytes |
コンパイル時間 | 1,842 ms |
コンパイル使用メモリ | 167,848 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-28 14:54:17 |
合計ジャッジ時間 | 3,621 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 2 ms
5,376 KB |
testcase_16 | AC | 2 ms
5,376 KB |
testcase_17 | AC | 2 ms
5,376 KB |
testcase_18 | AC | 2 ms
5,376 KB |
testcase_19 | AC | 2 ms
5,376 KB |
testcase_20 | AC | 2 ms
5,376 KB |
testcase_21 | AC | 2 ms
5,376 KB |
testcase_22 | AC | 2 ms
5,376 KB |
testcase_23 | AC | 2 ms
5,376 KB |
testcase_24 | AC | 2 ms
5,376 KB |
testcase_25 | AC | 2 ms
5,376 KB |
testcase_26 | AC | 2 ms
5,376 KB |
testcase_27 | AC | 2 ms
5,376 KB |
testcase_28 | AC | 2 ms
5,376 KB |
testcase_29 | AC | 2 ms
5,376 KB |
testcase_30 | AC | 2 ms
5,376 KB |
testcase_31 | AC | 2 ms
5,376 KB |
testcase_32 | AC | 2 ms
5,376 KB |
testcase_33 | AC | 2 ms
5,376 KB |
testcase_34 | AC | 2 ms
5,376 KB |
testcase_35 | AC | 2 ms
5,376 KB |
testcase_36 | AC | 2 ms
5,376 KB |
testcase_37 | AC | 2 ms
5,376 KB |
testcase_38 | AC | 2 ms
5,376 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define ll long long #define all(x) x.begin(),x.end() #define rep(i,a,b) for(int i=a;i<=b;i++) #define rep_r(i,a,b) for(int i=a;i>=b;i--) #define each(a,x) for (auto& x : a) using pi = pair<int,int>; using pl = pair<ll,ll>; using vi = vector<int>; using vl = vector<ll>; #define sz(x) int(x.size()) #define so(x) sort(all(x)) #define so_r(x) sort(all(x),greater<int>()) #define lb lower_bound #define ub upper_bound const char nl = '\n'; int dx[4] = {1,-1,0,0}; int dy[4] = {0,0,1,-1}; int bit_cnt(int x){ return __builtin_popcount(x); } ll bex(ll a, ll b, ll mod = 1e9 + 7){ll res = 1LL; while(b){ if (b&1) res = res * a % mod; a = a * a % mod; b >>= 1;} return res;} template<class t,class u> bool chmax(t&a,u b){if(a<b){a=b;return true;}else return false;} template<class t,class u> bool chmin(t&a,u b){if(b<a){a=b;return true;}else return false;} const int MOD = 998244353; const int N = 5e5 + 5; const ll INF = 1e16; int n; ll k; string s; // https://yukicoder.me/problems/no/78 // brief: n icecreams in 1 box, 3 types of icecream: "truot", "trung 1 que", "trung 2 que" // lay lan luot que kem theo thu tu, type cua que kem duoc ghi trong S (0 || 1 || 2) // can mua it nhat bao nhieu que kem de co the an duoc it nhat k que kem // n <= 50, k <= 2e9 pair<int,int> one_box(){ int buy = 0; int remain = 0; rep(i,1,n){ buy++; int j = i; int prize = s[i-1] - '0'; while (prize && j < n) { prize--; j++; if (j > i) prize += s[j-1] - '0'; } i = j; remain = prize; } return {buy, remain}; } int find1(int k){ int buy = 0; if (k == 0) return 0; rep(i,1,n){ buy++; int j = i; int prize = s[i-1] - '0'; while (prize && j < n) { prize--; j++; if (j > i) prize += s[j-1] - '0'; } i = j; if (i >= k) return buy; } return n; } void solve(){ cin >> n >> k >> s; pair<int,int> p = one_box(); int buy = p.first, remain = p.second; // cout << buy << ' ' << remain << nl; if (k <= n) { cout << find1(k) << nl; return; } if (k > n && remain >= buy){ cout << buy << nl; return; } // extra buy times we need to spend for full fill other box int next_buy = buy - remain; ll boxes = k / n; // total full-boxes we need to buy ll still = k % n; // number of icecream still need to buy ll ans = 1 * buy + next_buy * (boxes - 1) + max(find1(still) - remain, 0); cout << ans << nl; } int main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); int t = 1; // cin >> t; while (t--){ solve(); } }