結果

問題 No.2796 Small Matryoshka
ユーザー mkawa2mkawa2
提出日時 2024-06-28 21:39:52
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 878 ms / 2,000 ms
コード長 5,216 bytes
コンパイル時間 334 ms
コンパイル使用メモリ 82,432 KB
実行使用メモリ 118,136 KB
最終ジャッジ日時 2024-06-28 21:40:03
合計ジャッジ時間 10,326 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 75 ms
67,328 KB
testcase_01 AC 70 ms
67,584 KB
testcase_02 AC 72 ms
67,712 KB
testcase_03 AC 70 ms
67,584 KB
testcase_04 AC 71 ms
67,584 KB
testcase_05 AC 224 ms
82,400 KB
testcase_06 AC 631 ms
109,416 KB
testcase_07 AC 78 ms
69,888 KB
testcase_08 AC 525 ms
101,144 KB
testcase_09 AC 866 ms
114,324 KB
testcase_10 AC 878 ms
118,136 KB
testcase_11 AC 867 ms
117,408 KB
testcase_12 AC 552 ms
91,248 KB
testcase_13 AC 269 ms
81,164 KB
testcase_14 AC 522 ms
88,956 KB
testcase_15 AC 322 ms
82,252 KB
testcase_16 AC 360 ms
83,196 KB
testcase_17 AC 594 ms
96,736 KB
testcase_18 AC 669 ms
103,356 KB
testcase_19 AC 305 ms
84,380 KB
testcase_20 AC 374 ms
85,984 KB
testcase_21 AC 588 ms
95,456 KB
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ソースコード

diff # 

import sys

# sys.setrecursionlimit(200005)
# sys.set_int_max_str_digits(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()

dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
# inf = -1-(-1 << 31)
inf = -1-(-1 << 62)

# md = 10**9+7
md = 998244353

# Thanks for tatyam
# https://github.com/tatyam-prime/SortedSet/blob/main/SortedMultiset.py
import math
from bisect import bisect_left, bisect_right, insort
from typing import Generic, Iterable, Iterator, TypeVar, Optional, List

T = TypeVar('T')

class SortedMultiset(Generic[T]):
    BUCKET_RATIO = 50
    REBUILD_RATIO = 170

    def _build(self, a=None) -> None:
        "Evenly divide `a` into buckets."
        if a is None: a = list(self)
        size = self.size = len(a)
        bucket_size = int(math.ceil(math.sqrt(size/self.BUCKET_RATIO)))
        self.a = [a[size*i//bucket_size: size*(i+1)//bucket_size] for i in range(bucket_size)]

    def __init__(self, a: Iterable[T] = []) -> None:
        "Make a new SortedMultiset from iterable. / O(N) if sorted / O(N log N)"
        a = list(a)
        if not all(a[i] <= a[i+1] for i in range(len(a)-1)):
            a = sorted(a)
        self._build(a)

    def __iter__(self) -> Iterator[T]:
        for i in self.a:
            for j in i: yield j

    def __reversed__(self) -> Iterator[T]:
        for i in reversed(self.a):
            for j in reversed(i): yield j

    def __len__(self) -> int:
        return self.size

    def __repr__(self) -> str:
        return "SortedMultiset"+str(self.a)

    def __str__(self) -> str:
        s = str(list(self))
        return "{"+s[1: len(s)-1]+"}"

    def _find_bucket(self, x: T) -> List[T]:
        "Find the bucket which should contain x. self must not be empty."
        for a in self.a:
            if x <= a[-1]: return a
        return a

    def __contains__(self, x: T) -> bool:
        if self.size == 0: return False
        a = self._find_bucket(x)
        i = bisect_left(a, x)
        return i != len(a) and a[i] == x

    def count(self, x: T) -> int:
        "Count the number of x."
        return self.index_right(x)-self.index(x)

    def add(self, x: T) -> None:
        "Add an element. / O(√N)"
        if self.size == 0:
            self.a = [[x]]
            self.size = 1
            return
        a = self._find_bucket(x)
        insort(a, x)
        self.size += 1
        if len(a) > len(self.a)*self.REBUILD_RATIO:
            self._build()

    def discard(self, x: T) -> bool:
        "Remove an element and return True if removed. / O(√N)"
        if self.size == 0: return False
        a = self._find_bucket(x)
        i = bisect_left(a, x)
        if i == len(a) or a[i] != x: return False
        a.pop(i)
        self.size -= 1
        if len(a) == 0: self._build()
        return True

    def lt(self, x: T) -> Optional[T]:
        "Find the largest element < x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] < x:
                return a[bisect_left(a, x)-1]

    def le(self, x: T) -> Optional[T]:
        "Find the largest element <= x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] <= x:
                return a[bisect_right(a, x)-1]

    def gt(self, x: T) -> Optional[T]:
        "Find the smallest element > x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] > x:
                return a[bisect_right(a, x)]

    def ge(self, x: T) -> Optional[T]:
        "Find the smallest element >= x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] >= x:
                return a[bisect_left(a, x)]

    def __getitem__(self, x: int) -> T:
        "Return the x-th element, or IndexError if it doesn't exist."
        if x < 0: x += self.size
        if x < 0: raise IndexError
        for a in self.a:
            if x < len(a): return a[x]
            x -= len(a)
        raise IndexError

    def index(self, x: T) -> int:
        "Count the number of elements < x."
        ans = 0
        for a in self.a:
            if a[-1] >= x:
                return ans+bisect_left(a, x)
            ans += len(a)
        return ans

    def index_right(self, x: T) -> int:
        "Count the number of elements <= x."
        ans = 0
        for a in self.a:
            if a[-1] > x:
                return ans+bisect_right(a, x)
            ans += len(a)
        return ans

n=II()
ss=SortedMultiset()
for _ in range(n):
    a,b=LI()
    ss.add((a,b))

cnt=-1
while len(ss):
    a,b=ss[0]
    ss.discard((a, b))
    cnt+=1
    while ss:
        p=ss.index((b,-1))
        if p==len(ss):break
        na,nb=ss[p]
        ss.discard((na,nb))
        b=nb
print(cnt)
0