結果
| 問題 |
No.2795 Perfect Number
|
| コンテスト | |
| ユーザー |
june19312
|
| 提出日時 | 2024-06-28 22:54:56 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 84 ms / 2,000 ms |
| コード長 | 2,706 bytes |
| コンパイル時間 | 125 ms |
| コンパイル使用メモリ | 82,260 KB |
| 実行使用メモリ | 76,144 KB |
| 最終ジャッジ日時 | 2024-06-28 22:55:00 |
| 合計ジャッジ時間 | 2,686 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 35 |
ソースコード
import sys
sys.setrecursionlimit(10**6)
import pypyjit
pypyjit.set_param('max_unroll_recursion=-1')
def gcd(a, b):
while b: a, b = b, a % b
return a
def isPrimeMR(n):
assert 0 < n < 2**64
if n == 1: return 0
d = n - 1
d = d // (d & -d)
L = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]
for a in L:
if n == a: return 1
t = d
y = pow(a, t, n)
if y == 1: continue
while y != n - 1:
y = (y * y) % n
if y == 1 or t == n - 1: return 0
t <<= 1
return 1
def findFactorRho(n):
m = 1 << n.bit_length() // 8
for c in range(1, 99):
f = lambda x: (x * x + c) % n
y, r, q, g = 2, 1, 1, 1
while g == 1:
x = y
for i in range(r):
y = f(y)
k = 0
while k < r and g == 1:
ys = y
for i in range(min(m, r - k)):
y = f(y)
q = q * abs(x - y) % n
g = gcd(q, n)
k += m
r <<= 1
if g == n:
g = 1
while g == 1:
ys = f(ys)
g = gcd(abs(x - ys), n)
if g < n:
if isPrimeMR(g): return g
elif isPrimeMR(n // g): return n // g
return findFactorRho(g)
def bunkai(x):
bunkaians = []
for bunkaiind,bunkaival in x.items():
for j in range(bunkaival):
bunkaians.append(bunkaiind)
return bunkaians
def primeFactor(n):
i = 2
ret = {}
rhoFlg = 0
while i*i <= n:
k = 0
while n % i == 0:
n //= i
k += 1
if k: ret[i] = k
i += 1 + i % 2
if i == 101 and n >= 2 ** 20:
while n > 1:
if isPrimeMR(n):
ret[n], n = 1, 1
else:
rhoFlg = 1
j = findFactorRho(n)
k = 0
while n % j == 0:
n //= j
k += 1
ret[j] = k
if n > 1: ret[n] = 1
if rhoFlg: ret = {x: ret[x] for x in sorted(ret)}
return ret
N = int(input())
tmp = primeFactor(N)
tmp1,tmp2 = [],[]
for ind,val in tmp.items():
tmp1.append(ind)
tmp2.append(val)
ans = 0
def check(x):
tmpans = 1
for j in range(len(x)):
tmpans *= tmp1[j] ** x[j]
global ans
ans += tmpans
return
def dfs(x,y):
if len(x) == len(tmp1):
check(x)
return
for i in range(tmp2[y]+1):
x.append(i)
dfs(x,y+1)
x.pop()
dfs([],0)
if N*2 == ans:
print("Yes")
else:
print("No")
june19312