結果
| 問題 | No.2807 Have Another Go (Easy) |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2024-07-12 23:56:43 |
| 言語 | C++17 (gcc 15.2.0 + boost 1.90.0) |
| 結果 |
AC
|
| 実行時間 | 23 ms / 3,000 ms |
| コード長 | 1,006 bytes |
| 記録 | |
| コンパイル時間 | 2,704 ms |
| コンパイル使用メモリ | 277,584 KB |
| 実行使用メモリ | 9,268 KB |
| 最終ジャッジ日時 | 2026-07-05 05:27:39 |
| 合計ジャッジ時間 | 4,581 ms |
|
ジャッジサーバーID (参考情報) |
judge3_0 / judge1_0 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 46 |
コンパイルメッセージ
main.cpp: In function 'int main()':
main.cpp:14:36: warning: ignoring return value of 'std::basic_ostream<_CharT, _Traits>* std::basic_ios<_CharT, _Traits>::tie() const [with _CharT = char; _Traits = std::char_traits<char>]', declared with attribute 'nodiscard' [-Wunused-result]
14 | ios::sync_with_stdio(0);cin.tie();
| ~~~~~~~^~
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@15/15.3.0/include/c++/15/ios:48,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@15/15.3.0/include/c++/15/istream:42,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@15/15.3.0/include/c++/15/sstream:42,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@15/15.3.0/include/c++/15/complex:50,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@15/15.3.0/include/c++/15/x86_64-pc-linux-gnu/bits/stdc++.h:141,
from main.cpp:1:
/home/linuxbrew/.linuxbrew/Cellar/gcc@15/15.3.0/include/c++/15/bits/basic_ios.h:310:7: note: declared here
310 | tie() const
| ^~~
ソースコード
#include <bits/stdc++.h>
#include <atcoder/all>
using ll = long long;
#define MOD 1000000007
#define Mod 998244353
const int MAX = 1000000005;
const long long INF = 1000000000000000005LL;
using namespace std;
using namespace atcoder;
using mint = modint998244353;
int main() {
ios::sync_with_stdio(0);cin.tie();
int N, M, k;
cin >> N >> M >> k;
vector<int> C(k);
for (int i = 0; i < k; i++) cin >> C[i];
vector<mint> dp(2*N);
dp[0] = 1;
for (int i = 1; i < 2*N; i++) {
for (int j = 1; j <= 6; j++) {
if (i - j < 0) break;
dp[i] += dp[i - j];
}
}
for (int i = 0; i < k; i++) {
mint ans = 0;
for (int j = 1; j <= 6; j++) {
ans += dp[C[i]] * dp[2*N - j - C[i]] * (7 - j);
if (N - j - C[i] >= 0) ans += dp[N + C[i]] * dp[N - j - C[i]] * (7 - j);
if (N - j - C[i] >= 0) ans -= dp[C[i]] * dp[N] * dp[N - j - C[i]] * (7 - j);
}
cout << ans.val() << endl;
}
}