結果
問題 | No.2813 Cookie |
ユーザー | Yoyoyo8128 |
提出日時 | 2024-07-16 01:07:16 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 54 ms / 2,000 ms |
コード長 | 9,499 bytes |
コンパイル時間 | 4,210 ms |
コンパイル使用メモリ | 236,908 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-07-16 01:07:23 |
合計ジャッジ時間 | 7,218 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 44 ms
6,940 KB |
testcase_02 | AC | 47 ms
6,940 KB |
testcase_03 | AC | 42 ms
6,940 KB |
testcase_04 | AC | 51 ms
6,940 KB |
testcase_05 | AC | 51 ms
6,944 KB |
testcase_06 | AC | 45 ms
6,940 KB |
testcase_07 | AC | 49 ms
6,944 KB |
testcase_08 | AC | 46 ms
6,940 KB |
testcase_09 | AC | 53 ms
6,940 KB |
testcase_10 | AC | 50 ms
6,944 KB |
testcase_11 | AC | 45 ms
6,940 KB |
testcase_12 | AC | 42 ms
6,940 KB |
testcase_13 | AC | 40 ms
6,940 KB |
testcase_14 | AC | 43 ms
6,940 KB |
testcase_15 | AC | 54 ms
6,940 KB |
testcase_16 | AC | 44 ms
6,948 KB |
testcase_17 | AC | 49 ms
6,940 KB |
testcase_18 | AC | 36 ms
6,940 KB |
testcase_19 | AC | 40 ms
6,940 KB |
testcase_20 | AC | 39 ms
6,944 KB |
testcase_21 | AC | 49 ms
6,944 KB |
testcase_22 | AC | 37 ms
6,944 KB |
testcase_23 | AC | 35 ms
6,940 KB |
testcase_24 | AC | 34 ms
6,940 KB |
testcase_25 | AC | 43 ms
6,940 KB |
testcase_26 | AC | 1 ms
6,944 KB |
testcase_27 | AC | 2 ms
6,940 KB |
testcase_28 | AC | 1 ms
6,944 KB |
testcase_29 | AC | 2 ms
6,940 KB |
testcase_30 | AC | 2 ms
6,944 KB |
コンパイルメッセージ
main.cpp: In function 'std::ostream& operator<<(std::ostream&, const std::map<T, S>&)': main.cpp:198:16: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions] 198 | for (auto &[key, val] : m) | ^
ソースコード
#include <bits/stdc++.h> using namespace std; #include <atcoder/all> using namespace atcoder; using ll = long long; using ld = long double; using pii = pair<int, int>; using pli = pair<ll, int>; using pll = pair<ll, ll>; typedef vector<ll> vi; typedef vector<vi> vvi; const string Yes = "Yes"; const string No = "No"; const string YES = "YES"; const string NO = "NO"; const string abc = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; const ll MOD = 1000000007; const ll mod = 998244353; const long long inf = 1LL << 60; const long double PI = 3.141592653589793; #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #define _GLIBCXX_DEBUG #define pb push_back #define mp make_pair #define all(x) (x).begin(), (x).end() #define fi first #define se second const vector<int> dx = {0, 1, 0, -1}; const vector<int> dy = {1, 0, -1, 0}; using mint = modint998244353; using Mint = modint1000000007; #define YESNO(T) \ if (T) \ { \ cout << "YES" << endl; \ } \ else \ { \ cout << "NO" << endl; \ } #define yesno(T) \ if (T) \ { \ cout << "yes" << endl; \ } \ else \ { \ cout << "no" << endl; \ } #define YesNo(T) \ if (T) \ { \ cout << "Yes" << endl; \ } \ else \ { \ cout << "No" << endl; \ } #define inV(vec) \ for (ll i = 0; i < vec.size(); i++) \ cin >> vec[i]; #define outV(vec) \ for (ll i = 0; i < vec.size(); i++) \ { \ cout << vec[i] << " "; \ } \ cout << endl; #define print(s) cout << s << endl; #define updiv(n, x) (n + x - 1) / x #define rounddiv(n, x) (ll)((double)(n) / (double)(x) + 0.5) #define fix(n) fixed << setprecision(n); #define ioinit \ ios::sync_with_stdio(false); \ std::cin.tie(nullptr) template <typename T> inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); } template <typename T> inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); } template <class T> ll sum(const T &a) { return accumulate(all(a), 0LL); } #pragma region inout // pair_out template <typename T, typename U> ostream &operator<<(ostream &os, const pair<T, U> &p) { os << p.first << " " << p.second; return os; } // pair_in template <typename T, typename U> istream &operator>>(istream &is, pair<T, U> &p) { is >> p.first >> p.second; return is; } // vector_out template <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { int s = (int)v.size(); for (int i = 0; i < s; i++) os << (i ? " " : "") << v[i]; return os; } // vector_in template <typename T> istream &operator>>(istream &is, vector<T> &v) { for (auto &x : v) is >> x; return is; } //__int128_t_in istream &operator>>(istream &is, __int128_t &x) { string S; is >> S; x = 0; int flag = 0; for (auto &c : S) { if (c == '-') { flag = true; continue; } x *= 10; x += c - '0'; } if (flag) x = -x; return is; } //__uint128_t_in istream &operator>>(istream &is, __uint128_t &x) { string S; is >> S; x = 0; for (auto &c : S) { x *= 10; x += c - '0'; } return is; } //__int128_t_out ostream &operator<<(ostream &os, __int128_t x) { if (x == 0) return os << 0; if (x < 0) os << '-', x = -x; string S; while (x) S.push_back('0' + x % 10), x /= 10; reverse(begin(S), end(S)); return os << S; } //__uint128_t_out ostream &operator<<(ostream &os, __uint128_t x) { if (x == 0) return os << 0; string S; while (x) S.push_back('0' + x % 10), x /= 10; reverse(begin(S), end(S)); return os << S; } // vector<vector>_out template <typename T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { for (int i = 0; i < (int)v.size(); i++) { os << v[i] << endl; } return os; } // vector<vector<vector>>_out template <typename T> ostream &operator<<(ostream &os, const vector<vector<vector<T>>> &v) { for (int i = 0; i < (int)v.size(); i++) { os << "i = " << i << endl; os << v[i]; } return os; } // map_out template <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &m) { for (auto &[key, val] : m) { os << key << ":" << val << " "; } return os; } // set_out template <typename T> ostream &operator<<(ostream &os, const set<T> &st) { auto itr = st.begin(); for (int i = 0; i < (int)st.size(); i++) { os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; } // multiset_out template <typename T> ostream &operator<<(ostream &os, const multiset<T> &st) { auto itr = st.begin(); for (int i = 0; i < (int)st.size(); i++) { os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; } // queue_out template <typename T> ostream &operator<<(ostream &os, queue<T> q) { while (q.size()) { os << q.front() << " "; q.pop(); } return os; } // deque_out template <typename T> ostream &operator<<(ostream &os, deque<T> q) { while (q.size()) { os << q.front() << " "; q.pop_front(); } return os; } // stack_out template <typename T> ostream &operator<<(ostream &os, stack<T> st) { while (st.size()) { os << st.top() << " "; st.pop(); } return os; } // priority_queue_out template <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq) { while (pq.size()) { os << pq.top() << " "; pq.pop(); } return os; } #if __has_include(<atcoder/all>) // 998244353_in istream &operator>>(istream &a, mint &b) { long long tmp; a >> tmp; b = tmp; return a; } // 998244353_out ostream &operator<<(ostream &a, mint &b) { a << b.val(); return a; } // 1000000007_in istream &operator>>(istream &a, Mint &b) { long long tmp; a >> tmp; b = tmp; return a; } // 1000000007_out ostream &operator<<(ostream &a, Mint &b) { a << b.val(); return a; } #endif #pragma endregion inout // 繰り返し二乗法 ll modpow(ll a, ll n, ll mod) { if (a == 0) { return 0; } ll res = 1; while (n > 0) { if (n & 1) res = res * a % mod; a = a * a % mod; n >>= 1; } return res; } // 割り算 ll Div(ll a, ll b, ll m) { return (a * modpow(b, m - 2, m)) % m; } // 階乗 vector<ll> fact(1); void fac(ll N, ll m) { fact[0] = 1; for (int i = 1; i <= N; i++) { ll ppp = i; while (ppp % m == 0) { ppp /= m; } fact.pb(fact[i - 1] * (ppp)); fact[i] %= m; } } ll v(ll n, ll p) { ll aaans = 0; ll nppp = n; while (nppp > 0) { aaans += nppp / p; nppp /= p; } return aaans; } // 組み合わせ ll comb(ll n, ll r, ll m) { if (n < r) { return 0; } if (r < 0) { return 0; } if (n < 0) { return 0; } return Div(fact[n], fact[r] * fact[n - r] % m, m); } ll mex(ll a, ll b) { if (a > b) { swap(a, b); } if (a != 0) { return 0; } else { if (b != 1) { return 1; } else { return 2; } } } template <typename T> struct Edge { int to; T cost; }; using Graph = vector<vector<Edge<long long>>>; // cost の型を long long に指定 /* tree_diamiter : dfs を用いて重み付き木 T の直径を求める 計算量: O(N) */ template <typename T> pair<T, int> dfs(const Graph &G, int u, int par) { // 最遠点間距離と最遠点を求める pair<T, int> ret = make_pair((T)0, u); for (auto e : G[u]) { if (e.to == par) continue; auto next = dfs<T>(G, e.to, u); next.first += e.cost; ret = max(ret, next); } return ret; } template <typename T> T tree_diamiter(const Graph &G) { pair<T, int> p = dfs<T>(G, 0, -1); pair<T, int> q = dfs<T>(G, p.second, -1); return q.first; } ll di(pll a,pll b){ return (a.fi-b.fi)*(a.fi-b.fi)+(a.se-b.se)*(a.se-b.se); } ll gcd(ll x, ll y) { if (y == 0) { return x; } else { return gcd(y, x % y); } } int main() { ll T; cin>>T; while(T--){ ll a; cin>>a; ll Gru=0; for(int i=0;i<a;i++){ ll A; cin>>A; if(A<=4){ Gru^=((A+1)/2); }else{ ll tmp=(A-2)/3; tmp*=4; if(A%3==1)tmp+=2; Gru^=tmp; } } if(Gru==0){ print("Bob"); }else{ print("Alice"); } } }