結果
問題 | No.2813 Cookie |
ユーザー | 👑 binap |
提出日時 | 2024-07-19 23:17:34 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 57 ms / 2,000 ms |
コード長 | 2,664 bytes |
コンパイル時間 | 4,620 ms |
コンパイル使用メモリ | 261,976 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-07-19 23:17:43 |
合計ジャッジ時間 | 7,223 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 46 ms
5,248 KB |
testcase_02 | AC | 50 ms
5,376 KB |
testcase_03 | AC | 46 ms
5,376 KB |
testcase_04 | AC | 54 ms
5,376 KB |
testcase_05 | AC | 57 ms
5,376 KB |
testcase_06 | AC | 50 ms
5,376 KB |
testcase_07 | AC | 54 ms
5,376 KB |
testcase_08 | AC | 50 ms
5,376 KB |
testcase_09 | AC | 57 ms
5,376 KB |
testcase_10 | AC | 55 ms
5,376 KB |
testcase_11 | AC | 48 ms
5,376 KB |
testcase_12 | AC | 46 ms
5,376 KB |
testcase_13 | AC | 44 ms
5,376 KB |
testcase_14 | AC | 49 ms
5,376 KB |
testcase_15 | AC | 47 ms
5,376 KB |
testcase_16 | AC | 47 ms
5,376 KB |
testcase_17 | AC | 54 ms
5,376 KB |
testcase_18 | AC | 41 ms
5,376 KB |
testcase_19 | AC | 44 ms
5,376 KB |
testcase_20 | AC | 45 ms
5,376 KB |
testcase_21 | AC | 55 ms
5,376 KB |
testcase_22 | AC | 42 ms
5,376 KB |
testcase_23 | AC | 40 ms
5,376 KB |
testcase_24 | AC | 39 ms
5,376 KB |
testcase_25 | AC | 48 ms
5,376 KB |
testcase_26 | AC | 2 ms
5,376 KB |
testcase_27 | AC | 2 ms
5,376 KB |
testcase_28 | AC | 2 ms
5,376 KB |
testcase_29 | AC | 2 ms
5,376 KB |
testcase_30 | AC | 2 ms
5,376 KB |
コンパイルメッセージ
main.cpp: In lambda function: main.cpp:41:9: warning: control reaches end of non-void function [-Wreturn-type] 41 | }; | ^
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef vector<int> vi; typedef vector<long long> vl; typedef vector<vector<int>> vvi; typedef vector<vector<long long>> vvl; typedef long double ld; typedef pair<int, int> P; ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} void solve(){ auto g = [&](int x){ if(x == 0) return 0; if(x == 1) return 1; if(x == 2) return 1; if(x == 3) return 2; if(x == 4) return 2; if(x == 5) return 4; if(x == 6) return 4; if(x % 3 == 1) return (x - 1) / 3 * 4 - 2; if(x % 3 == 2) return (x - 1) / 3 * 4; if(x % 3 == 0) return (x - 1) / 3 * 4; }; int n; cin >> n; vector<int> a(n); cin >> a; int res = 0; rep(i, n) res ^= g(a[i]); if(res == 0) cout << "Bob\n"; else cout << "Alice\n"; } int main(){ int t; cin >> t; rep(_, t) solve(); return 0; }