結果
| 問題 |
No.2012 Largest Triangle
|
| コンテスト | |
| ユーザー |
tnakao0123
|
| 提出日時 | 2024-07-23 17:54:00 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,580 bytes |
| コンパイル時間 | 733 ms |
| コンパイル使用メモリ | 62,896 KB |
| 最終ジャッジ日時 | 2025-02-23 17:54:16 |
|
ジャッジサーバーID (参考情報) |
judge1 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 17 WA * 24 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:38:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
38 | scanf("%d", &n);
| ~~~~~^~~~~~~~~~
main.cpp:39:36: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
39 | for (int i = 0; i < n; i++) scanf("%lld%lld", xs + i, ys + i);
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~
ソースコード
/* -*- coding: utf-8 -*-
*
* 2012.cc: No.2012 Largest Triangle - yukicoder
*/
#include<cstdio>
#include<cmath>
#include<algorithm>
#include<utility>
using namespace std;
/* constant */
const int MAX_N = 200000;
const long long LINF = 1LL << 60;
/* typedef */
using ll = long long;
using pdi = pair<double,int>;
/* global variables */
ll xs[MAX_N], ys[MAX_N];
pdi tis[MAX_N];
/* subroutines */
inline ll cross(int i, int j) {
return xs[i] * ys[j] - xs[j] * ys[i];
}
/* main */
int main() {
int n;
scanf("%d", &n);
for (int i = 0; i < n; i++) scanf("%lld%lld", xs + i, ys + i);
for (int i = 0; i < n; i++) tis[i] = {atan2(ys[i], xs[i]), i};
sort(tis, tis + n);
ll minc = LINF, maxc = -LINF;
int j0 = -1, j1 = -1;
for (int j = 0; j < n; j++) {
ll c = cross(0, tis[j].second);
//printf(" c=%lld,j=%d\n", c, j);
if (minc > c) minc = c, j0 = j;
if (maxc < c) maxc = c, j1 = j;
}
//printf("minc=%lld,j0=%d maxc=%lld,j1=%d\n", minc, j0, maxc, j1);
for (int i = 1; i < n; i++) {
ll c0 = cross(tis[i].second, tis[j0].second);
while (j0 != i) {
int jj = (j0 + 1) % n;
ll cc = cross(tis[i].second, tis[jj].second);
if (cc >= c0) break;
c0 = cc, j0 = jj;
}
minc = min(minc, c0);
ll c1 = cross(tis[i].second, tis[j1].second);
while (j1 != i) {
int jj = (j1 + 1) % n;
ll cc = cross(tis[i].second, tis[jj].second);
if (cc <= c1) break;
c1 = cc, j1 = jj;
}
maxc = max(maxc, c1);
}
ll maxs = max(-minc, maxc);
printf("%lld\n", maxs);
return 0;
}
tnakao0123