結果

問題 No.2857 Div Array
ユーザー aogeraaogera
提出日時 2024-08-25 16:20:45
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
実行時間 -
コード長 5,220 bytes
コンパイル時間 8,627 ms
コンパイル使用メモリ 352,376 KB
実行使用メモリ 359,320 KB
最終ジャッジ日時 2024-08-25 16:20:58
合計ジャッジ時間 11,748 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
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ファイルパターン 結果
other AC * 11 TLE * 1 -- * 18
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ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<bits/stdc++.h>
#include <atcoder/all>
using ull = unsigned long long;
using namespace std;
using namespace atcoder;
using vst = vector<string>;
using ll = long long;
using ld = long double;
using P = pair<ll,ll>;
using vl = vector<ll>;
using vvl = vector<vl>;
using vP = vector<P>;
#define rep(i, n) for (ll i = 0; i < n; i++)
#define repp(i,k,n) for (ll i = k; i < n; i++)
#define per(i,s,e) for(ll i = s; i >= e; i--)
#define all(v) v.begin(),v.end()
#define yesno(a) a ? cout << "Yes" << '\n' : cout << "No" << '\n'
#define YESNO(a) a ? cout << "YES" << '\n' : cout << "NO" << '\n'
#define UNOmap unordered_map
#define UNOset unordered_set
#define chmax(a,b) a=max(a,b)
#define chmin(a,b) a=min(a,b)
#define debug(x) cerr << #x << " = " << x << '\n'
template<class... T>void in(T&... a){(cin >> ... >> a);}
template<class T, class... Ts>void out(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << '\n';}
template<class T> void vin2(vector<T> &u,vector<T> &v){for(ll i = 0; i < (ll)v.size(); i++) in(u[i],v[i]);}
template<class T> void vin(vector<T> &v){for(ll i = 0; i < (ll)v.size(); i++)in(v[i]);}
template<class T> void vout(vector<T> &v){for(ll i = 0; i < (ll)v.size(); i++) cout << v[i] << ' ';cout << "\n";}
ll INF = 1152921504606846976;ll MOD =998244353; ll MOD1 =1000000007;
/* INF = 1LL << 60 */
#define sl(...) ll __VA_ARGS__; in(__VA_ARGS__)
using mint = modint998244353;
using mint1 = modint1000000007;
using mintn = modint;
using vm = vector<mint>;
using vvm = vector<vm>;
vl dx = {0,0,1,-1}, dy = {1,-1,0,0};
//----------------------------------------------
template< class T >
struct Matrix {
vector< vector< T > > A;
Matrix() {}
Matrix(size_t n, size_t m) : A(n, vector< T >(m, 0)) {}
Matrix(size_t n) : A(n, vector< T >(n, 0)) {};
size_t height() const {
return (A.size());
}
size_t width() const {
return (A[0].size());
}
inline const vector< T > &operator[](int k) const {
return (A.at(k));
}
inline vector< T > &operator[](int k) {
return (A.at(k));
}
static Matrix I(size_t n) {
Matrix mat(n);
for(int i = 0; i < n; i++) mat[i][i] = 1;
return (mat);
}
Matrix &operator+=(const Matrix &B) {
size_t n = height(), m = width();
assert(n == B.height() && m == B.width());
for(int i = 0; i < n; i++)
for(int j = 0; j < m; j++)
(*this)[i][j] += B[i][j];
return (*this);
}
Matrix &operator-=(const Matrix &B) {
size_t n = height(), m = width();
assert(n == B.height() && m == B.width());
for(int i = 0; i < n; i++)
for(int j = 0; j < m; j++)
(*this)[i][j] -= B[i][j];
return (*this);
}
Matrix &operator*=(const Matrix &B) {
size_t n = height(), m = B.width(), p = width();
assert(p == B.height());
vector< vector< T > > C(n, vector< T >(m, 0));
for(int i = 0; i < n; i++)
for(int j = 0; j < m; j++)
for(int k = 0; k < p; k++)
C[i][j] = (C[i][j] + (*this)[i][k] * B[k][j]);
A.swap(C);
return (*this);
}
Matrix &operator^=(long long k) {
Matrix B = Matrix::I(height());
while(k > 0) {
if(k & 1) B *= *this;
*this *= *this;
k >>= 1LL;
}
A.swap(B.A);
return (*this);
}
Matrix operator+(const Matrix &B) const {
return (Matrix(*this) += B);
}
Matrix operator-(const Matrix &B) const {
return (Matrix(*this) -= B);
}
Matrix operator*(const Matrix &B) const {
return (Matrix(*this) *= B);
}
Matrix operator^(const long long k) const {
return (Matrix(*this) ^= k);
}
friend ostream &operator<<(ostream &os, Matrix &p) {
size_t n = p.height(), m = p.width();
for(int i = 0; i < n; i++) {
os << "[";
for(int j = 0; j < m; j++) {
os << p[i][j] << (j + 1 == m ? "]\n" : ",");
}
}
return (os);
}
T determinant() {
Matrix B(*this);
assert(width() == height());
T ret = 1;
for(int i = 0; i < width(); i++) {
int idx = -1;
for(int j = i; j < width(); j++) {
if(B[j][i] != 0) idx = j;
}
if(idx == -1) return (0);
if(i != idx) {
ret *= -1;
swap(B[i], B[idx]);
}
ret *= B[i][i];
T vv = B[i][i];
for(int j = 0; j < width(); j++) {
B[i][j] /= vv;
}
for(int j = i + 1; j < width(); j++) {
T a = B[j][i];
for(int k = 0; k < width(); k++) {
B[j][k] -= B[i][k] * a;
}
}
}
return (ret);
}
};
int main(){
ios::sync_with_stdio(false);cin.tie(nullptr);cout<<fixed<<setprecision(15);
//==============================================
ll N, M, K;
in(N,M,K);
Matrix<mint> Mt(M,M);
rep(i,M) rep(j,M){
Mt[i][j] =0;
if(abs(j-i) <= K) Mt[i][j]=1;
}
Matrix<mint> Nt(M,1);
repp(i,1,M+1){
Nt[M/i-1][0]++;
}
rep(i,M) rep(j,M){
Mt[i][j] =0;
if(abs(j-i) <= K) Mt[i][j]=Nt[i][0];
}
Mt ^=N-1;
rep(i,M){
rep(j,M){
//out(Mt[i][j].val());
}
}
Mt *= Nt;
mint ans = 0;
rep(i,M){
//out(Mt[i][0].val());
ans += Mt[i][0];
}
out(ans.val());
}
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