結果

問題 No.2873 Kendall's Tau
ユーザー rlangevin
提出日時 2024-09-06 22:08:37
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 1,106 ms / 4,500 ms
コード長 2,570 bytes
コンパイル時間 467 ms
コンパイル使用メモリ 82,248 KB
実行使用メモリ 200,724 KB
最終ジャッジ日時 2024-09-06 22:10:18
合計ジャッジ時間 17,522 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
input = sys.stdin.readline
from collections import *
class Fenwick_Tree:
def __init__(self, n):
self._n = n
self.data = [0] * n
def add(self, p, x):
assert 0 <= p < self._n
p += 1
while p <= self._n:
self.data[p - 1] += x
p += p & -p
def sum(self, l, r):
assert 0 <= l <= r <= self._n
return self._sum(r) - self._sum(l)
def _sum(self, r):
s = 0
while r > 0:
s += self.data[r - 1]
r -= r & -r
return s
# T.sum(0, x) <= kx
def get(self, k):
k += 1
x, r = 0, 1
while r < self._n:
r <<= 1
len = r
while len:
if x + len - 1 < self._n:
if self.data[x + len - 1] < k:
k -= self.data[x + len - 1]
x += len
len >>= 1
return x
def __str__(self):
temp = []
for i in range(self._n):
temp.append(str(self.sum(i, i + 1)))
return ' '.join(temp)
from bisect import *
from copy import deepcopy
def compress(lst):
'''
B: lst
idx_to_val: index
val_to_idx: index
'''
B = []
val_to_idx = {}
idx_to_val = deepcopy(lst)
idx_to_val = list(set(idx_to_val))
idx_to_val.sort()
for i in range(len(lst)):
ind = bisect_left(idx_to_val, lst[i])
B.append(ind)
for i in range(len(B)):
val_to_idx[lst[i]] = B[i]
return B, idx_to_val, val_to_idx
N = int(input())
X, Y = [], []
D = []
for i in range(N):
x, y = map(int, input().split())
X.append(x)
Y.append(y)
X, _, _ = compress(X)
Y, _, _ = compress(Y)
D = [[] for i in range(N)]
for i in range(N):
D[X[i]].append(Y[i])
Cx = Counter(X)
Cy = Counter(Y)
R, S = N * (N - 1) // 2, N * (N - 1) // 2
for k, v in Cx.items():
R -= v * (v - 1) // 2
for k, v in Cy.items():
S -= v * (v - 1) // 2
P = 0
T = Fenwick_Tree(N + 1)
for x in range(N):
for y in D[x]:
T.add(y, 1)
for x in range(N):
for y in D[x]:
T.add(y, -1)
for y in D[x]:
P += T.sum(y + 1, N + 1)
Q = 0
T = Fenwick_Tree(N + 1)
for x in range(N-1, -1, -1):
for y in D[x]:
T.add(y, 1)
for x in range(N-1, -1, -1):
for y in D[x]:
T.add(y, -1)
for y in D[x]:
Q += T.sum(y + 1, N + 1)
print((P - Q) / (R * S) ** 0.5)
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