結果

問題 No.1569 Nixoracci's Number
コンテスト
ユーザー flippergo
提出日時 2024-10-13 14:03:58
言語 Rust
(1.83.0 + proconio)
結果
AC  
実行時間 148 ms / 2,000 ms
コード長 1,824 bytes
コンパイル時間 19,851 ms
コンパイル使用メモリ 376,236 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-10-13 14:04:21
合計ジャッジ時間 16,083 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge5
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 3
other AC * 21
権限があれば一括ダウンロードができます
コンパイルメッセージ
warning: variable `X` should have a snake case name
 --> src/main.rs:3:11
  |
3 | fn matmul(X: &Vec<Vec<i64>>, Y: &Vec<Vec<i64>>, N: usize) -> Vec<Vec<i64>> {
  |           ^ help: convert the identifier to snake case (notice the capitalization): `x`
  |
  = note: `#[warn(non_snake_case)]` on by default

warning: variable `Y` should have a snake case name
 --> src/main.rs:3:30
  |
3 | fn matmul(X: &Vec<Vec<i64>>, Y: &Vec<Vec<i64>>, N: usize) -> Vec<Vec<i64>> {
  |                              ^ help: convert the identifier to snake case (notice the capitalization): `y`

warning: variable `N` should have a snake case name
 --> src/main.rs:3:49
  |
3 | fn matmul(X: &Vec<Vec<i64>>, Y: &Vec<Vec<i64>>, N: usize) -> Vec<Vec<i64>> {
  |                                                 ^ help: convert the identifier to snake case: `n`

warning: variable `Z` should have a snake case name
 --> src/main.rs:4:13
  |
4 |     let mut Z = vec![vec![0; N]; N];
  |             ^ help: convert the identifier to snake case (notice the capitalization): `z`

warning: variable `X` should have a snake case name
  --> src/main.rs:15:11
   |
15 | fn matpow(X: &Vec<Vec<i64>>, k: i64, N: usize) -> Vec<Vec<i64>> {
   |           ^ help: convert the identifier to snake case (notice the capitalization): `x`

warning: variable `N` should have a snake case name
  --> src/main.rs:15:38
   |
15 | fn matpow(X: &Vec<Vec<i64>>, k: i64, N: usize) -> Vec<Vec<i64>> {
   |                                      ^ help: convert the identifier to snake case: `n`

warning: variable `I` should have a snake case name
  --> src/main.rs:16:13
   |
16 |     let mut I = vec![vec![0; N]; N];
   |             ^ help: convert the identifier to snake case (notice the capitalization): `i`

warning: variable `Y` should have a snake case name
  --> src/main.rs:32:13
   |
32 |         let Y = matmul(&half_pow, &half_pow, N);
   |             ^ help: convert the identifier to snake case (notice the capitalization): `y`

warnin

ソースコード

diff #
raw source code 

use std::io;

fn matmul(X: &Vec<Vec<i64>>, Y: &Vec<Vec<i64>>, N: usize) -> Vec<Vec<i64>> {
    let mut Z = vec![vec![0; N]; N];
    for i in 0..N {
        for j in 0..N {
            for k in 0..N {
                Z[i][j] ^= X[i][k] * Y[k][j];  // XOR 演算
            }
        }
    }
    Z
}

fn matpow(X: &Vec<Vec<i64>>, k: i64, N: usize) -> Vec<Vec<i64>> {
    let mut I = vec![vec![0; N]; N];
    for i in 0..N {
        I[i][i] = 1;  // 単位行列
    }

    if k == 0 {
        return I;
    } else if k == 1 {
        return X.clone();
    }

    if k % 2 == 0 {
        let half_pow = matpow(X, k / 2, N);
        return matmul(&half_pow, &half_pow, N);
    } else {
        let half_pow = matpow(X, (k - 1) / 2, N);
        let Y = matmul(&half_pow, &half_pow, N);
        return matmul(X, &Y, N);
    }
}

fn main() {
    let mut input = String::new();
    io::stdin().read_line(&mut input).expect("Failed to read line");
    let mut input_iter = input.split_whitespace();
    let N: usize = input_iter.next().unwrap().parse().expect("Failed to parse N");
    let K: i64 = input_iter.next().unwrap().parse().expect("Failed to parse K");

    let mut A = vec![];
    input.clear();
    io::stdin().read_line(&mut input).expect("Failed to read line");
    for num in input.split_whitespace() {
        A.push(num.parse::<i64>().expect("Failed to parse A element"));
    }

    let T = N + 1;
    let M = (K - 1) % T as i64;

    let mut A1 = vec![vec![0; N]; N];

    // A1行列の初期化
    for i in 0..(N - 1) {
        A1[i][i + 1] = 1;
    }
    for j in 0..N {
        A1[N - 1][j] = 1;
    }

    // A1をM回累乗した行列を計算
    let B = matpow(&A1, M, N);

    // 答えを計算
    let mut ans = 0;
    for i in 0..N {
        ans ^= B[0][i] * A[i];
    }

    println!("{}", ans);
}
0