結果
問題 | No.2977 Kth Xor Pair |
ユーザー |
|
提出日時 | 2024-12-03 19:52:53 |
言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,220 ms / 3,000 ms |
コード長 | 2,481 bytes |
コンパイル時間 | 1,859 ms |
コンパイル使用メモリ | 131,612 KB |
実行使用メモリ | 83,084 KB |
最終ジャッジ日時 | 2024-12-03 19:53:11 |
合計ジャッジ時間 | 16,849 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 34 |
ソースコード
// https://yukicoder.me/submissions/1029779#include <iostream>#include <vector>#include <cmath>#include <utility>#include <algorithm>using namespace std;// Function to count 0s and 1s in bit position `i`pair<long long, long long> count01(const vector<long long>& L, long long i) {long long czero = 0, cone = 0;for (long long a : L) {if ((a >> i) & 1) {cone++;} else {czero++;}}return {czero, cone};}// Function to divide the list into 0-group and 1-group based on bit position `i`pair<vector<long long>, vector<long long>> div01(const vector<long long>& L, long long i) {vector<long long> rzero, rone;for (long long a : L) {if ((a >> i) & 1) {rone.push_back(a);} else {rzero.push_back(a);}}return {rzero, rone};}signed main() {// Inputlong long N, K;cin >> N >> K;vector<long long> A(N);for (long long i = 0; i < N; ++i) {cin >> A[i];}// Calculation & OutputK--;K *= 2;K += N;vector<pair<vector<long long>, vector<long long>>> pairs = {{A, A}};long long ans = 0;for (long long i = 29; i >= 0; --i) {ans <<= 1;long long czero = 0;for (auto& p : pairs) {auto [lz, lo] = count01(p.first, i);auto [rz, ro] = count01(p.second, i);czero += lz * rz + lo * ro;}vector<pair<vector<long long>, vector<long long>>> npairs;if (K >= czero) {ans += 1;K -= czero;for (auto& p : pairs) {auto [lz, lo] = div01(p.first, i);auto [rz, ro] = div01(p.second, i);if (!lz.empty() && !ro.empty()) {npairs.push_back({lz, ro});}if (!lo.empty() && !rz.empty()) {npairs.push_back({lo, rz});}}} else {for (auto& p : pairs) {auto [lz, lo] = div01(p.first, i);auto [rz, ro] = div01(p.second, i);if (!lz.empty() && !rz.empty()) {npairs.push_back({lz, rz});}if (!lo.empty() && !ro.empty()) {npairs.push_back({lo, ro});}}}pairs = npairs;}cout << ans << endl;return 0;}