結果
問題 | No.2986 Permutation Puzzle |
ユーザー |
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提出日時 | 2024-12-11 01:36:18 |
言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 7 ms / 2,000 ms |
コード長 | 2,835 bytes |
コンパイル時間 | 4,053 ms |
コンパイル使用メモリ | 280,308 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-12-11 01:36:24 |
合計ジャッジ時間 | 5,353 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 40 |
ソースコード
#include<bits/stdc++.h>namespace {#pragma GCC diagnostic ignored "-Wunused-function"#include<atcoder/all>#pragma GCC diagnostic warning "-Wunused-function"using namespace std;using namespace atcoder;#define rep(i,n) for(int i = 0; i < (int)(n); i++)#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; i--)#define all(x) begin(x), end(x)#define rall(x) rbegin(x), rend(x)template<class T> bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } else return false; }template<class T> bool chmin(T& a, const T& b) { if (b < a) { a = b; return true; } else return false; }using ll = long long;using P = pair<int,int>;using VI = vector<int>;using VVI = vector<VI>;using VL = vector<ll>;using VVL = vector<VL>;using A = array<int, 10>;} int main() {ios::sync_with_stdio(false);cin.tie(0);int n, k;cin >> n >> k;int a[10][10]{}, b[10][10]{};rep(i, n) rep(j, n) cin >> a[i][j], a[i][j]--;rep(i, n) rep(j, n) cin >> b[i][j], b[i][j]--;vector<tuple<int, int, A>> hist;A pr, pc;rep(i, 10) pr[i] = i, pc[i] = i;vector<P> ans;auto dfs = [&](auto&& self, int rest) -> void {bool is_same = [&]() {rep(i, n) rep(j, n) if (a[pr[i]][pc[j]] != b[i][j]) return false;return true;}();if (is_same) {while (hist.size()) {auto [rc, now, p] = hist.back(); hist.pop_back();int cnt = 1;bool visited[10]{};rep(i, n) if (!visited[i]) {int c = 0;while (!visited[i]) visited[i] = true, c++, i = p[i];cnt = lcm(c, cnt);}A inv;rep(i, n) inv[p[i]] = i;rep(_, cnt - 1) {ans.emplace_back(rc, now);if (rc == 0) {A npr{};rep(j, n) npr[a[pr[now]][pc[j]]] = j;auto pre = pr;rep(i, n) pr[i] = pre[npr[i]];} else {A npc{};rep(i, n) npc[a[pr[i]][pc[now]]] = i;auto pre = pc;rep(j, n) pc[j] = pre[npc[j]];}now = inv[now];}}rep(i, n) assert(pr[i] == i && pc[i] == i);cout << ans.size() << '\n';for (auto [rc, i] : ans) {cout << "RC"[rc] << ' ' << i + 1 << '\n';}exit(0);}if (rest == 0) return;rep(i, n) {A npr{};rep(j, n) npr[a[pr[i]][pc[j]]] = j;auto pre = pr;rep(i, n) pr[i] = pre[npr[i]];hist.emplace_back(0, a[pre[i]][pc[i]], npr);self(self, rest - 1);hist.pop_back();pr = pre;}rep(j, n) {A npc{};rep(i, n) npc[a[pr[i]][pc[j]]] = i;auto pre = pc;rep(j, n) pc[j] = pre[npc[j]];hist.emplace_back(1, a[pr[j]][pre[j]], npc);self(self, rest - 1);hist.pop_back();pc = pre;}};dfs(dfs, k);assert(false);}