結果

問題 No.2920 Blood Type
ユーザー solo
提出日時 2024-12-22 12:12:52
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
AC  
実行時間 33 ms / 2,000 ms
コード長 1,483 bytes
コンパイル時間 294 ms
コンパイル使用メモリ 12,800 KB
実行使用メモリ 11,008 KB
最終ジャッジ日時 2024-12-22 12:12:55
合計ジャッジ時間 2,364 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 36
権限があれば一括ダウンロードができます

ソースコード

diff # 

s, t = [input() for _ in range(2)]


def sindan(s, t):
	kai = ''
	kekka = {'A': 0, 'B': 0, 'AB': 0, 'O': 0}
	f = [s, t]
	if 'AA' in f:
		if f.count('AA') == 2:
			kekka['A'] = 100
		elif 'AB' in f:
			kekka['A'] = 50
			kekka['AB'] = 50
		elif 'AO' in f:
			kekka['A'] = 100
		elif 'BB' in f:
			kekka['AB'] = 100
		elif 'BO' in f:
			kekka['A'] = 50
			kekka['AB'] = 50
		else:
			kekka['A'] = 100

	elif 'AB' in f:
		if f.count('AB') == 2:
			kekka['A'] = 25
			kekka['B'] = 25
			kekka['AB'] = 50
		elif 'AO' in f:
			kekka['A'] = 50
			kekka['B'] = 25
			kekka['AB'] = 25
		elif 'BB' in f:
			kekka['B'] = 50
			kekka['AB'] = 50
		elif 'BO' in f:
			kekka['A'] = 25
			kekka['B'] = 50
			kekka['AB'] = 25
		else:
			kekka['A'] = 50
			kekka['B'] = 50

	elif 'AO' in f:
		if f.count('AO') == 2:
			kekka['A'] = 75
			kekka['O'] = 25
		elif 'BB' in f:
			kekka['B'] = 50
			kekka['AB'] = 50
		elif 'BO' in f:
			kekka['A'] = 25
			kekka['B'] = 25
			kekka['AB'] = 25
			kekka['O'] = 25
		else:
			kekka['A'] = 50
			kekka['O'] = 50

	elif 'BB' in f:
		if f.count('BB') == 2:
			kekka['B'] = 100
		elif 'BO' in f:
			kekka['B'] = 100
		else:
			kekka['B'] = 100

	elif 'BO' in f:
		if f.count('BO') == 2:
			kekka['B'] = 75
			kekka['O'] = 25
		else:
			kekka['B'] = 50
			kekka['O'] = 50

	elif 'OO' in f:
		if f.count('OO') == 2:
			kekka['O'] = 100

	for value in kekka.values():
		kai += str(value)
		for n in range(len(kekka.keys())-1):
			kai += ' '
	print(kai)	

sindan(s, t)
0