結果
問題 | No.3031 曲面の向き付け |
ユーザー |
|
提出日時 | 2025-02-21 21:51:05 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 687 ms / 2,000 ms |
コード長 | 2,518 bytes |
コンパイル時間 | 446 ms |
コンパイル使用メモリ | 82,596 KB |
実行使用メモリ | 176,908 KB |
最終ジャッジ日時 | 2025-02-21 21:51:33 |
合計ジャッジ時間 | 10,599 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 29 |
ソースコード
import sysinput = lambda :sys.stdin.readline()[:-1]ni = lambda :int(input())na = lambda :list(map(int,input().split()))yes = lambda :print("yes");Yes = lambda :print("Yes");YES = lambda : print("YES")no = lambda :print("no");No = lambda :print("No");NO = lambda : print("NO")#######################################################################from collections import defaultdictclass UnionFind():def __init__(self, n):self.n = nself.parents = [-1] * ndef find(self, x):if self.parents[x] < 0:return xelse:self.parents[x] = self.find(self.parents[x])return self.parents[x]def union(self, x, y):x = self.find(x)y = self.find(y)if x == y:returnif self.parents[x] > self.parents[y]:x, y = y, xself.parents[x] += self.parents[y]self.parents[y] = xdef size(self, x):return -self.parents[self.find(x)]def same(self, x, y):return self.find(x) == self.find(y)def members(self, x):root = self.find(x)return [i for i in range(self.n) if self.find(i) == root]def roots(self):return [i for i, x in enumerate(self.parents) if x < 0]def group_count(self):return len(self.roots())def all_group_members(self):group_members = defaultdict(list)for member in range(self.n):group_members[self.find(member)].append(member)return group_membersdef __str__(self):return '\n'.join(f'{r}: {m}' for r, m in self.all_group_members().items())def g(x, y):if x < y:return x * D + y, 0else:return y * D + x, 1D = 10 ** 8 + 100m = ni()p = [na() for i in range(m)]s = []for i in range(m):for j in range(3):s.append(g(p[i][j], p[i][(j+1) % 3])[0])dic = {x:i for i, x in enumerate(s)}n = len(s)f = [[] for i in range(n)]uf = UnionFind(m * 2)for i in range(m):for j in range(3):x, y = g(p[i][j], p[i][(j+1) % 3])f[dic[x]].append((i, y))for i in range(n):if len(f[i]) > 2:NO()exit()elif len(f[i]) == 2:a, b = f[i][0], f[i][1]if a[1] == b[1]:uf.union(a[0], b[0] + m)uf.union(a[0] + m, b[0])else:uf.union(a[0], b[0])uf.union(a[0] + m, b[0] + m)for i in range(m):if uf.same(i, i + m):NO()exit()YES()