結果
問題 | No.3028 No.9999 |
ユーザー |
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提出日時 | 2025-02-22 02:51:14 |
言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 4,000 ms |
コード長 | 2,287 bytes |
コンパイル時間 | 3,851 ms |
コンパイル使用メモリ | 301,324 KB |
実行使用メモリ | 6,824 KB |
最終ジャッジ日時 | 2025-02-22 02:51:20 |
合計ジャッジ時間 | 5,181 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 23 |
ソースコード
#include<bits/stdc++.h>namespace {#pragma GCC diagnostic ignored "-Wunused-function"#include<atcoder/all>#pragma GCC diagnostic warning "-Wunused-function"using namespace std;using namespace atcoder;#define rep(i,n) for(int i = 0; i < (int)(n); i++)#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; i--)#define all(x) begin(x), end(x)#define rall(x) rbegin(x), rend(x)template<class T> bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } else return false; }template<class T> bool chmin(T& a, const T& b) { if (b < a) { a = b; return true; } else return false; }using ll = long long;using P = pair<int,int>;using VI = vector<int>;using VVI = vector<VI>;using VL = vector<ll>;using VVL = vector<VL>;template<class T>vector<pair<T, int>> factorize(T x) {vector<pair<T, int>> res;for(T p = 2; p * p <= x; p++) {int cnt = 0;while(x % p == 0) x /= p, cnt++;if (cnt) res.emplace_back(p, cnt);}if (x > 1) res.emplace_back(x, 1);return res;}long long reduced_totient(long long a) {long long res = 1;for(auto [p, cnt]: factorize(a)) {if (p == 2) {res = cnt <= 2 ? 1LL << (cnt - 1) : 1LL << (cnt - 2);continue;}long long phi = p - 1;for(int i = cnt - 1; i > 0; i--) phi *= p;res = lcm(res, phi);}return res;}ll calc_ord(ll x, ll m) {assert(m >= 1 && gcd(x, m) == 1);if (m <= 2) return 1;x %= m;if (x < 0) x += m;auto fs = factorize(reduced_totient(m));int n = fs.size();vector<ll> dp(n), pe(n);for (int i = 0; auto [p, e] : fs) {ll v = 1;while (e--) v *= p;pe[i++] = v;}dp[0] = x;int k = bit_ceil(0U + n);while (k != 1) {int k2 = k / 2;for (int l = 0; l + k2 < n; l += k) {int c = l + k2, r = min(n, l + k);ll v = 1;for (int i = l; i < c; i++) v *= pe[i];dp[c] = pow_mod(dp[l], v, m);v = 1;for (int i = c; i < r; i++) v *= pe[i];dp[l] = pow_mod(dp[l], v, m);}k = k2;}ll res = 1;for (int i = 0; i < n; i++) {ll xi = dp[i];int p = fs[i].first;while (xi != 1) xi = pow_mod(xi, p, m), res *= p;}return res;}} int main() {ios::sync_with_stdio(false);cin.tie(0);int n;cin >> n;cout << calc_ord(10, n) << '\n';}