結果

問題 No.3041 非対称じゃんけん
ユーザー timi
提出日時 2025-02-28 22:04:45
言語 PyPy3
(7.3.15)
結果
RE  
実行時間 -
コード長 2,122 bytes
コンパイル時間 362 ms
コンパイル使用メモリ 82,400 KB
実行使用メモリ 74,640 KB
最終ジャッジ日時 2025-02-28 22:04:48
合計ジャッジ時間 3,313 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 1
other AC * 1 WA * 28 RE * 1
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

def main():
from sys import stdin, setrecursionlimit
input = stdin.readline
readline = stdin.readline
import sys
sys.setrecursionlimit(10**7)
from collections import deque
# https://atcoder.jp/contests/practice2/submissions/16789717
mod, g, ig = 998244353, 3, 332748118
W = [pow(g, (mod-1)>>i, mod) for i in range(24)]
iW = [pow(ig, (mod-1)>>i, mod) for i in range(24)]
def NTT(k, A): # k: int, &A: List[int]
for l in range(k, 0, -1):
d = 1<<l - 1
U = [1]
for i in range(d):
U.append(U[-1] * W[l] % mod)
for i in range(1<<k - l):
for j in range(d):
s = i*2*d + j
A[s], A[s+d] = (A[s]+A[s+d]) % mod, U[j] * (A[s]-A[s+d]) % mod
def iNTT(k, A): # k: int, &A: List[int]
for l in range(1, k + 1):
d = 1<<l - 1
for i in range(1<<k - l):
u = 1
for j in range(i*2*d, (i*2+1)*d):
A[j+d] *= u
A[j], A[j+d] = (A[j]+A[j+d]) % mod, (A[j]-A[j+d]) % mod
u = u * iW[l] % mod
def convolve(A, B): # A,B: List[int]
n0 = len(A) + len(B) - 1
k = (n0).bit_length()
n = 1 << k
A = A + [0] * (n-len(A))
B = B + [0] * (n-len(B))
C = [0] * n # A使
NTT(k, A)
NTT(k, B)
for i in range(n):
C[i] = A[i] * B[i] % mod
iNTT(k, C)
invn = pow(n, mod-2, mod) # fftifft1/N
for i in range(n0):
C[i] = C[i] * invn % mod
return C[:n0] # List[int]
N,F = map(int,input().split())
A = list(map(int,input().split()))
B = list(map(int,input().split()))
C = list(map(int,input().split()))
D=[1];c=1
for i in range(3):
E=[0]*61
E[A[i]]+=1;E[B[i]]+=1;E[C[i]]+=1
c+=max(A[i],B[i],C[i])
D=list(convolve(D,E))
D=D[:c]
ans=0
for d in D:
if d!=0:
ans+=1
print(ans)
main()
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