結果

問題 No.2365 Present of good number
ユーザー detteiuu
提出日時 2025-03-04 04:25:33
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 1,487 bytes
コンパイル時間 349 ms
コンパイル使用メモリ 82,676 KB
実行使用メモリ 75,028 KB
最終ジャッジ日時 2025-03-04 04:25:38
合計ジャッジ時間 3,979 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 17 WA * 22
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

from heapq import heappush, heappop
def factorization(n):
arr = []
temp = n
for i in range(2, int(-(-n**0.5//1))+1):
if temp%i == 0:
cnt = 0
while temp%i == 0:
cnt += 1
temp //= i
arr.append([i, cnt])
if temp != 1:
arr.append([temp, 1])
if arr == []:
arr.append([n, 1])
return arr
def matrix(a, b):
ans = [[0]*len(b[0]) for _ in range(len(a))]
for i in range(len(a)):
for j in range(len(b[0])):
ans[i][j] = sum(a[i][k]*b[k][j]%MOD for k in range(len(b)))%MOD
return ans
N, K = map(int, input().split())
MOD = 10**9+7
que = []
S = set()
for n, c in factorization(N):
heappush(que, -n)
S.add(n)
while que:
a = -heappop(que)
for n, c in factorization(a+1):
if n not in S:
heappush(que, -n)
S.add(n)
S = sorted(S)
D = dict()
for i, s in enumerate(S):
D[s] = i
dp = [[[0]*len(D) for _ in range(len(D))]]
for i, s in enumerate(S):
n = s+1
for j, s2 in enumerate(S):
cnt = 0
while n%s2 == 0:
n //= s2
cnt += 1
dp[0][j][i] = cnt
for _ in range(59):
dp.append(matrix(dp[-1], dp[-1]))
A = [[0] for _ in range(len(D))]
for n, c in factorization(N):
A[D[n]][0] = c
for i in range(60):
if 1<<i & K:
A = matrix(dp[i], A)
ans = 1
for i in range(len(D)):
ans *= pow(S[i], A[i][0], MOD)
ans %= MOD
print(ans)
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