結果
問題 | No.236 鴛鴦茶 |
ユーザー |
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提出日時 | 2025-03-07 09:23:56 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 749 bytes |
コンパイル時間 | 342 ms |
コンパイル使用メモリ | 27,648 KB |
実行使用メモリ | 8,608 KB |
最終ジャッジ日時 | 2025-03-07 09:23:57 |
合計ジャッジ時間 | 1,494 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | WA * 2 |
other | WA * 23 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:6:17: warning: format ‘%f’ expects argument of type ‘float*’, but argument 2 has type ‘double*’ [-Wformat=] 6 | scanf("%f%f",&ratio1,&overall1); | ~^ ~~~~~~~ | | | | | double* | float* | %lf main.cpp:6:19: warning: format ‘%f’ expects argument of type ‘float*’, but argument 3 has type ‘double*’ [-Wformat=] 6 | scanf("%f%f",&ratio1,&overall1); | ~^ ~~~~~~~~~ | | | | float* double* | %lf main.cpp:10:17: warning: format ‘%f’ expects argument of type ‘float*’, but argument 2 has type ‘double*’ [-Wformat=] 10 | scanf("%f%f",&ratio2,&overall2); | ~^ ~~~~~~~ | | | | | double* | float* | %lf main.cpp:10:19: warning: format ‘%f’ expects argument of type ‘float*’, but argument 3 has type ‘double*’ [-Wformat=] 10 | scanf("%f%f",&ratio2,&overall2); | ~^ ~~~~~~~~~ | | | | float* double* | %lf main.cpp:27:18: warning: format ‘%f’ expects argument of type ‘double’, but argument 2 has type ‘double*’ [-Wformat=] 27 | printf("%f",&ans); | ~^ ~~~~ | | | | | double* | double main.cpp:6:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 6 | scanf("%f%f",&ratio1,&overall1); | ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:10:14: warning: ignoring return value of ‘int
ソースコード
#include<stdio.h> int main(){ // 入力された値 double ratio1, overall1; scanf("%f%f",&ratio1,&overall1); //printf("比率1:%f 全体1:%f\n",ratio1,overall1); double ratio2, overall2; scanf("%f%f",&ratio2,&overall2); //printf("比率2:%f 全体2:%f\n",ratio2,overall2); // 1回に作る分量 double quantity1 = overall1 / ratio1; double quantity2 = overall2 / ratio2; //printf("分量1:%f 分量2:%f\n",quantity1,quantity2); // 全体製造量 double ans = 0; while(0 <= overall1 && 0 <= overall2){ overall1 -= quantity1; overall2 -= quantity2; //printf("計算後\n全体1:%f 全体2:%f",overall1,overall2); ans += (quantity1 + quantity2); //printf("製造量:%f\n",ans); } printf("%f",&ans); }