#1051204 (PyPy3) No.2131 Concon Substrings (COuNt Version)

• 問題: No.2131 Concon Substrings (COuNt Version)
• ユーザー: 已经死了
• 提出日時: 2025-03-09 01:28:06
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 404 ms / 2,000 ms
• コード長: 2,473 bytes
• コンパイル時間: 696 ms
• コンパイル使用メモリ: 82,448 KB
• 実行使用メモリ: 93,732 KB
• 最終ジャッジ日時: 2025-03-09 01:28:14
• 合計ジャッジ時間: 7,072 ms
• ジャッジサーバーID （参考情報）: judge4 / judge2

ファイルパターン	結果
sample	AC * 4
other	AC * 16

ソースコード

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import os,sys,random,threading
#sys.exit() 退出程序
#sys.setrecursionlimit(10**6) #调整栈空间
from random import randint,choice,shuffle
#randint(a,b)从[a,b]范围随机选择一个数
#choice(seq)seq可以是一个列表,元组或字符串,从seq中随机选取一个元素
#shuffle(x)将一个可变的序列x中的元素打乱
from copy import deepcopy
from io import BytesIO,IOBase
from types import GeneratorType
from functools import lru_cache,reduce
#reduce(op,迭代对象)
from bisect import bisect_left,bisect_right
#bisect_left(x) 大于等于x的第一个下标
#bisect_right(x) 大于x的第一个下标
from collections import Counter,defaultdict,deque
from itertools import accumulate,combinations,permutations
#accumulate(a)用a序列生成一个累积迭代器，一般list化前面放个[0]做前缀和用
#combinations(a,k)a序列选k个 组合迭代器
#permutations(a,k)a序列选k个 排列迭代器
from heapq import  heapify,heappop,heappush
#heapify将列表转为堆
from typing import Generic,Iterable,Iterator,TypeVar,Union,List
from string import ascii_lowercase,ascii_uppercase,digits
#小写字母，大写字母，十进制数字
from math import ceil,floor,sqrt,pi,factorial,gcd,log,log10,log2,inf
#ceil向上取整，floor向下取整 ，sqrt开方 ，factorial阶乘
from decimal import Decimal,getcontext
#Decimal(s) 实例化Decimal对象,一般使用字符串
#getcontext().prec=100 修改精度
from sys import stdin, stdout, setrecursionlimit
input = lambda: sys.stdin.readline().rstrip("\r\n")
MI = lambda :map(int,input().split())
li = lambda :list(MI())
ii = lambda :int(input())
mod = int(1e9 + 7) #998244353
inf = 1<<60
py = lambda :print("YES")
pn = lambda :print("NO")
DIRS = [(0, 1), (1, 0), (0, -1), (-1, 0)]  # 右下左上
DIRS8 = [(0, 1), (1, 1), (1, 0), (1, -1), (0, -1), (-1, -1), (-1, 0),(-1, 1)]  # →↘↓↙←↖↑↗
MOD=mod = 998244353
n=ii()
k=n//3+1
f0=[0]*(k+2) #f0[i]表示匹配了i次con，目前等待放一个c
f1=[0]*(k+2)
f2=[0]*(k+2)
f0[0]=1
for _ in range(n):
    nf0=[0]*(k+2) 
    nf1=[0]*(k+2)
    nf2=[0]*(k+2)
    for i in range(k+1):
        nf0[i]+=f0[i]*25
        nf1[i]+=f0[i]
        nf1[i]+=f1[i]*25
        nf2[i]+=f1[i]
        nf2[i]+=f2[i]*25
        nf0[i+1]+=f2[i]
        nf0[i]%=mod
        nf1[i]%=mod
        nf2[i]%=mod
        nf0[i+1]%=mod
    f0,f1,f2=nf0,nf1,nf2
res=0
for i in range(1,k+1):
    res+=(f0[i]+f1[i]+f2[i])*i
    res%=mod
print(res)
 
 
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