結果
問題 |
No.1340 おーじ君をさがせ
|
ユーザー |
![]() |
提出日時 | 2025-03-20 18:46:56 |
言語 | PyPy3 (7.3.15) |
結果 |
MLE
|
実行時間 | - |
コード長 | 1,626 bytes |
コンパイル時間 | 311 ms |
コンパイル使用メモリ | 82,656 KB |
実行使用メモリ | 610,736 KB |
最終ジャッジ日時 | 2025-03-20 18:47:51 |
合計ジャッジ時間 | 7,664 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 49 MLE * 1 -- * 9 |
ソースコード
def main(): import sys n, m, T = map(int, sys.stdin.readline().split()) adj = [set() for _ in range(n)] for _ in range(m): a, b = map(int, sys.stdin.readline().split()) adj[a].add(b) steps = [ {0} ] seen = {} mask = 1 << 0 seen[mask] = 0 # steps[0] is after 0 moves for t in range(1, T + 1): current_set = steps[-1] new_set = set() for u in current_set: if len(adj[u]) == 0: # If any vertex has no outgoing edges, it leads to disappearance # But we process all possible in the current step # So if u has no adj, then none added from u continue for v in adj[u]: new_set.add(v) # Check if new_set is empty if not new_set: print(0) return # Calculate mask mask = 0 for v in new_set: mask |= 1 << v # Check if mask exists in seen if mask in seen: prev_step = seen[mask] cycle_length = t - prev_step remaining = T - prev_step remainder = remaining % cycle_length final_step = prev_step + remainder print(len(steps[final_step])) return else: # Check if new_set is same as last step if steps and new_set == steps[-1]: print(len(new_set)) return seen[mask] = t steps.append(new_set) # After all steps simulated print(len(steps[-1])) if __name__ == '__main__': main()