結果
| 問題 | 
                            No.1376 Simple LPS Problem
                             | 
                    
| コンテスト | |
| ユーザー | 
                             lam6er
                         | 
                    
| 提出日時 | 2025-03-20 20:58:19 | 
| 言語 | PyPy3  (7.3.15)  | 
                    
| 結果 | 
                             
                                WA
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 1,450 bytes | 
| コンパイル時間 | 177 ms | 
| コンパイル使用メモリ | 82,248 KB | 
| 実行使用メモリ | 54,584 KB | 
| 最終ジャッジ日時 | 2025-03-20 20:58:52 | 
| 合計ジャッジ時間 | 6,813 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge2 / judge4 | 
(要ログイン)
| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 2 | 
| other | AC * 43 WA * 17 | 
ソースコード
N, K = map(int, input().split())
if K == 1:
    if N == 1:
        print(0)
    else:
        print(-1)
elif K > N:
    print(-1)
else:
    required_min = (N + 1) // 2
    if K < required_min:
        print(-1)
    else:
        if K == N:
            print('0' * N)
        else:
            # Construct the palindrome part
            if K % 2 == 0:
                half = K // 2
                first_part = ['0'] + ['1'] * (half - 1)
                first_part = first_part[:half]  # Ensure correct length
                second_part = first_part[::-1]
                palindrome = ''.join(first_part + second_part)
            else:
                m = (K - 1) // 2
                first_part = ['0'] + ['1'] * (m - 1)
                first_part = first_part[:m]  # first m-1 characters?
                middle = ['0']
                second_part = first_part[::-1]
                palindrome = ''.join(first_part + middle + second_part)
            
            # Append remaining characters
            remaining_length = N - K
            if remaining_length > 0:
                # The last character of the palindrome is '0' for even, '1' or '0' for odd
                # We append '1' followed by '0's to break any possible palindromes
                remaining = '1' + '0' * (remaining_length - 1)
                result = palindrome + remaining
            else:
                result = palindrome
            
            print(result)
            
            
            
        
            
lam6er