結果

問題 No.1352 Three Coins
ユーザー lam6er
提出日時 2025-03-20 21:06:29
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 1,055 bytes
コンパイル時間 193 ms
コンパイル使用メモリ 82,336 KB
実行使用メモリ 71,536 KB
最終ジャッジ日時 2025-03-20 21:06:36
合計ジャッジ時間 3,021 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 32 WA * 2
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import math
def compute_gcd(a, b, c):
return math.gcd(a, math.gcd(b, c))
A, B, C = map(int, input().split())
d = compute_gcd(A, B, C)
if d != 1:
print("INF")
else:
m = min(A, B, C)
# Use a maximum size to avoid memory issues. 1e6 is chosen based on problem constraints
max_n = 10**6
dp = [False] * (max_n + 1)
dp[0] = True # base case: 0 can be formed
consecutive = 0
result = 0
for i in range(1, max_n + 1):
# Check if current i can be formed by any of the coins
can_form = False
if i >= A and dp[i - A]:
can_form = True
if not can_form and i >= B and dp[i - B]:
can_form = True
if not can_form and i >= C and dp[i - C]:
can_form = True
dp[i] = can_form
if can_form:
consecutive += 1
if consecutive >= m:
break # All subsequent numbers can be formed
else:
consecutive = 0
result += 1 # Count numbers that cannot be formed
print(result)
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