結果
| 問題 |
No.3068 Speedrun (Hard)
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2025-03-21 22:12:09 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,773 bytes |
| コンパイル時間 | 4,784 ms |
| コンパイル使用メモリ | 254,304 KB |
| 実行使用メモリ | 11,672 KB |
| 最終ジャッジ日時 | 2025-03-21 22:12:23 |
| 合計ジャッジ時間 | 12,947 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge7 |
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| ファイルパターン | 結果 |
|---|---|
| sample | WA * 1 TLE * 1 |
| other | WA * 8 TLE * 1 -- * 23 |
ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int main(){
vector<int> a(4);
cin >> a;
int n;
cin >> n;
vector<int> p(4);
cin >> p;
int t;
cin >> t;
vector<vector<int>> alpha(n + 1);
vector<vector<int>> beta(n + 1);
for(int s0 = 0; s0 <= min(n, a[0] + a[1]); s0++){
int s1 = n - s0;
if(s1 > a[2] + a[3]) continue;
vector<int> f0;
for(int k0 = 0; k0 <= s0; k0++){
int k1 = s0 - k0;
if(k1 > a[1]) continue;
f0.push_back(p[0] * k0+ p[1] * k1);
}
vector<int> f1;
for(int k2 = 0; k2 <= s1; k2++){
int k3 = s1 - k2;
if(k3 > a[3]) continue;
f1.push_back(p[2] * k2+ p[3] * k3);
}
sort(f0.begin(), f0.end());
sort(f1.begin(), f1.end());
}
return 0;
}