結果

問題 No.3081 Make Palindromic Multiple
ユーザー 👑 potato167
提出日時 2025-03-29 02:23:32
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 12 ms / 1,000 ms
コード長 3,258 bytes
コンパイル時間 2,253 ms
コンパイル使用メモリ 198,256 KB
実行使用メモリ 7,324 KB
最終ジャッジ日時 2025-03-29 02:23:38
合計ジャッジ時間 5,214 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 54
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll=long long;
const ll ILL=2167167167167167167;
const int INF=2100000000;
#define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++)
#define all(p) p.begin(),p.end()
template<class T> using _pq = priority_queue<T, vector<T>, greater<T>>;
template<class T> int LB(vector<T> &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();}
template<class T> int UB(vector<T> &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();}
template<class T> bool chmin(T &a,T b){if(b<a){a=b;return 1;}else return 0;}
template<class T> bool chmax(T &a,T b){if(a<b){a=b;return 1;}else return 0;}
template<class T> void So(vector<T> &v) {sort(v.begin(),v.end());}
template<class T> void Sore(vector<T> &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});}
bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;}
template<class T> void vec_out(vector<T> &p,int ty=0){
    if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'<<p[i]<<'"';}cout<<"}\n";}
    else{if(ty==1){cout<<p.size()<<"\n";}for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout<<p[i];}cout<<"\n";}}
template<class T> T vec_min(vector<T> &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;}
template<class T> T vec_max(vector<T> &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;}
template<class T> T vec_sum(vector<T> &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;}
int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;}
template<class T> T square(T a){return a * a;}
// return val=p(N)
// a=p[0].first^p[0].second * ... *p[N-1].first^p[N-1].second
// for all i: p[i].first is prime number
// O(sqrt(val))
std::vector<std::pair<long long,long long>> Prime_factorization(long long val){
    assert(val>=1);
    if(val==1){
        return {};
    }
    int ind=0;
    std::vector<std::pair<long long,long long>> ans;
    for(long long i=2;i*i<=val;i++){
        if(val%i!=0) continue;
        ans.push_back({i,0});
        while(val%i==0){
            ans[ind].second++;
            val/=i;
        }
        ind++;
    }
    if(val!=1) ans.push_back({val,1});
    return ans;
}
void solve();
// CITRUS CURIO CITY / FREDERIC
int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int t = 1;
    // cin >> t;
    rep(i, 0, t) solve();
}
string tmp2 = "677726115990100000000000000000000000000000000000000000000000000000001099511627776";
string tmp5 = "52604613476359000000000000000000000000000000000000000000000000000000000000000000095367431640625";
void solve(){
    ll N;
    cin >> N;
    ll M = N;
    while (M % 5 == 0) M /= 5;
    while (M % 2 == 0) M /= 2;
    string base1 = tmp2;
    if (N % 5 == 0) base1 = tmp5;
    auto P = Prime_factorization(M);
    if (M == N){
        ll ans = M;
        for (auto [a, b] : P) ans /= a, ans *= (a - 1);
        cout << "1\n";
        cout << "9 " << ans << "\n";
        return;
    }
    ll ans = M;
    ll rem = 1;
    rep(i, 0, base1.size()){
        rem = rem * 10ll % M;
    }
    for (auto [a, b] : P){
        if (rem % a != 1) ans /= a, ans *= (a - 1);
    }
    cout << "1\n";
    cout << base1 << " " << ans << "\n";
}
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