結果
| 問題 |
No.1635 Let’s Sort Integers!!
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-03-31 15:21:16 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,709 bytes |
| コンパイル時間 | 3,451 ms |
| コンパイル使用メモリ | 219,624 KB |
| 実行使用メモリ | 8,672 KB |
| 最終ジャッジ日時 | 2025-03-31 15:21:35 |
| 合計ジャッジ時間 | 16,957 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 51 WA * 26 |
ソースコード
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define rep(i,a,b) for (int i = a; i < b; i++)
#define mp make_pair
#define pii pair<int,int>
#define pb push_back
#define pll pair<long long, long long>
#define fi first
#define se second
#define blahaj ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)
using namespace std;
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
typedef tree<pair<int,int>, null_type, less<pair<int,int>>, rb_tree_tag, tree_order_statistics_node_update> ordered_multiset;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<long long> vll;
typedef long long ll;
typedef long double ld;
ll mod = 1000000007;
const int N = 200000;
const int dx[4]{1, 0, -1, 0}, dy[4]{0, 1, 0, -1};
const char dir[4]{'D','R','U','L'};
#define all(x) begin(x), end(x)
string yes = "YES\n";
string no = "NO\n";
int inf = 1e9;
int main()
{
blahaj;
ll n, k;
cin >> n >> k;
if (k < n - 1 || k > n * (n - 1) / 2) cout << "-1\n";
else
{
ll cur = n - 1;
vector<bool> used(n + 1, false);
used[1] = true;
used[n] = true;
vector<int> ans;
ans.pb(1);
ans.pb(n);
ll last = n;
ll lo = 1;
ll hi = n;
ll need = k - cur;
while (need)
{
// cout << "NEED " << need << ' ' << lo << ' ' << hi << "\n";
if (last == hi)
{
lo++;
ll mxdiff = hi - lo;
if (mxdiff >= need)
{
ll val = hi - need;
ans.pb(val);
need = 0;
used[val] = true;
}
else
{
need -= mxdiff;
ans.pb(lo);
used[lo] = true;
}
last = lo;
}
else
{
hi--;
ll mxdiff = hi - lo;
if (mxdiff >= need)
{
ll val = lo + need;
ans.pb(val);
need = 0;
used[val] = true;
}
else
{
need -= mxdiff;
used[hi] = true;
ans.pb(hi);
}
last = hi;
}
}
cout << 1 << " ";
for (int i = 1; i <= n; i++) if (!used[i]) cout << i << ' ';
for (int i = 1; i < ans.size(); i++) cout << ans[i] << ' ';
cout << "\n";
}
}