結果
| 問題 |
No.298 話の伝達
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-03-31 17:26:56 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,948 bytes |
| コンパイル時間 | 213 ms |
| コンパイル使用メモリ | 82,560 KB |
| 実行使用メモリ | 55,040 KB |
| 最終ジャッジ日時 | 2025-03-31 17:27:50 |
| 合計ジャッジ時間 | 1,883 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 10 WA * 11 |
ソースコード
from collections import deque
def main():
n, m = map(int, input().split())
adj_out = [[] for _ in range(n)]
for _ in range(m):
a, b, c = map(int, input().split())
adj_out[a].append((b, c))
# Find reachable nodes using BFS
reachable = set()
queue = deque([0])
reachable.add(0)
while queue:
u = queue.popleft()
for (v, _) in adj_out[u]:
if v not in reachable:
reachable.add(v)
queue.append(v)
target = n - 1
if target not in reachable:
print(0.0)
return
# Build incoming edges for all nodes (original input edges)
incoming_edges = [[] for _ in range(n)]
for a in range(n):
for (b, c) in adj_out[a]:
incoming_edges[b].append((a, c))
# Build in_degree for reachable nodes only
in_degree = {u: 0 for u in reachable}
adj_reachable = [[] for _ in range(n)]
for u in reachable:
for (v, c) in adj_out[u]:
if v in reachable:
adj_reachable[u].append((v, c))
in_degree[v] += 1
# Kahn's algorithm to get topological order of reachable nodes
queue = deque()
for u in reachable:
if in_degree[u] == 0:
queue.append(u)
top_order = []
while queue:
u = queue.popleft()
top_order.append(u)
for (v, _) in adj_reachable[u]:
in_degree[v] -= 1
if in_degree[v] == 0:
queue.append(v)
# Calculate probabilities
prob = [0.0] * n
prob[0] = 1.0
for y in top_order:
if y == 0:
continue # prob[0] is already set
product = 1.0
for (a, c) in incoming_edges[y]:
contrib = prob[a] * (c / 100.0)
product *= (1.0 - contrib)
prob[y] = 1.0 - product
print("{0:.10f}".format(prob[target]))
if __name__ == "__main__":
main()
lam6er