結果
問題 |
No.298 話の伝達
|
ユーザー |
![]() |
提出日時 | 2025-03-31 17:26:56 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,948 bytes |
コンパイル時間 | 213 ms |
コンパイル使用メモリ | 82,560 KB |
実行使用メモリ | 55,040 KB |
最終ジャッジ日時 | 2025-03-31 17:27:50 |
合計ジャッジ時間 | 1,883 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 10 WA * 11 |
ソースコード
from collections import deque def main(): n, m = map(int, input().split()) adj_out = [[] for _ in range(n)] for _ in range(m): a, b, c = map(int, input().split()) adj_out[a].append((b, c)) # Find reachable nodes using BFS reachable = set() queue = deque([0]) reachable.add(0) while queue: u = queue.popleft() for (v, _) in adj_out[u]: if v not in reachable: reachable.add(v) queue.append(v) target = n - 1 if target not in reachable: print(0.0) return # Build incoming edges for all nodes (original input edges) incoming_edges = [[] for _ in range(n)] for a in range(n): for (b, c) in adj_out[a]: incoming_edges[b].append((a, c)) # Build in_degree for reachable nodes only in_degree = {u: 0 for u in reachable} adj_reachable = [[] for _ in range(n)] for u in reachable: for (v, c) in adj_out[u]: if v in reachable: adj_reachable[u].append((v, c)) in_degree[v] += 1 # Kahn's algorithm to get topological order of reachable nodes queue = deque() for u in reachable: if in_degree[u] == 0: queue.append(u) top_order = [] while queue: u = queue.popleft() top_order.append(u) for (v, _) in adj_reachable[u]: in_degree[v] -= 1 if in_degree[v] == 0: queue.append(v) # Calculate probabilities prob = [0.0] * n prob[0] = 1.0 for y in top_order: if y == 0: continue # prob[0] is already set product = 1.0 for (a, c) in incoming_edges[y]: contrib = prob[a] * (c / 100.0) product *= (1.0 - contrib) prob[y] = 1.0 - product print("{0:.10f}".format(prob[target])) if __name__ == "__main__": main()