#106275 (C++14) No.403 2^2^2

• 問題: No.403 2^2^2
• ユーザー: mayoko_
• 提出日時: 2016-07-22 23:16:12
• 言語: C++14 (gcc 13.3.0 + boost 1.87.0)
• 結果: AC
• 実行時間: 2 ms / 2,000 ms
• コード長: 1,791 bytes
• コンパイル時間: 1,021 ms
• コンパイル使用メモリ: 101,684 KB
• 実行使用メモリ: 5,248 KB
• 最終ジャッジ日時: 2024-11-06 15:16:49
• 合計ジャッジ時間: 1,840 ms
• ジャッジサーバーID （参考情報）: judge1 / judge4

ファイルパターン	結果
sample	AC * 3
other	AC * 27

ソースコード

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#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
//#include<cctype>
#include<climits>
#include<iostream>
#include<string>
#include<vector>
#include<map>
//#include<list>
#include<queue>
#include<deque>
#include<algorithm>
//#include<numeric>
#include<utility>
//#include<memory>
#include<functional>
#include<cassert>
#include<set>
#include<stack>
#include<random>
const int dx[] = {1, 0, -1, 0};
const int dy[] = {0, -1, 0, 1};
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef pair<int, int> pii;
ll mod_pow(ll x, ll p, ll MOD) {
    if (x == 0) return 0;
    ll a = 1;
    while (p) {
        if (p%2) a = a*x%MOD;
        x = x*x%MOD;
        p/=2;
    }
    return a;
}
pair<pair<ll, ll>, ll> unko(string s) {
    int n = s.size();
    pair<pair<ll, ll>, ll> ret;
    int div = 0;
    for (int i = 0; i < n; i++) {
        if (s[i] == '^') {
            if (ret.first.first == 0) {
                ret.first.first = stoll(s.substr(0, i));
                div = i+1;
            } else {
                ret.first.second = stoll(s.substr(div, i-div));
                ret.second = stoll(s.substr(i+1));
            }
        }
    }
    return ret;
}
const ll MOD = 1e9+7;
ll solve1(ll A, ll B, ll C) {
    ll tmp = mod_pow(A%MOD, B, MOD);
    return mod_pow(tmp, C, MOD);
}
ll solve2(ll A, ll B, ll C) {
    ll tmp = mod_pow(B%(MOD-1), C, MOD-1);
    return mod_pow(A%MOD, tmp, MOD);
}
int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    ll A, B, C;
    {
        string s;
        cin >> s;
        auto p = unko(s);
        A = p.first.first, B = p.first.second, C = p.second;
    }
    cout << solve1(A, B, C) << " " << solve2(A, B, C) << endl;
    return 0;
}
 
 
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