結果
| 問題 |
No.3085 Easy Problems
|
| コンテスト | |
| ユーザー |
pengin_2000
|
| 提出日時 | 2025-04-04 21:42:06 |
| 言語 | C (gcc 13.3.0) |
| 結果 |
AC
|
| 実行時間 | 424 ms / 2,000 ms |
| コード長 | 2,118 bytes |
| コンパイル時間 | 713 ms |
| コンパイル使用メモリ | 26,496 KB |
| 実行使用メモリ | 7,848 KB |
| 最終ジャッジ日時 | 2025-04-04 21:42:28 |
| 合計ジャッジ時間 | 15,678 ms |
|
ジャッジサーバーID (参考情報) |
judge6 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 31 |
コンパイルメッセージ
main.c: In function ‘main’:
main.c:123:9: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
123 | scanf("%d", &n);
| ^~~~~~~~~~~~~~~
main.c:126:17: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
126 | scanf("%d %d", &A[i], &B[i]);
| ^~~~~~~~~~~~~~~~~~~~~~~~~~~~
main.c:140:9: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
140 | scanf("%d", &q);
| ^~~~~~~~~~~~~~~
main.c:143:17: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
143 | scanf("%d %d", &x, &y);
| ^~~~~~~~~~~~~~~~~~~~~~
ソースコード
#include<stdio.h>
int A[200005], B[200005];
int h[200005], l, z;
int comp_h(int a, int b)
{
if (z == 0)
{
if (h[a] > h[b])
return 1;
else
return -1;
}
else
{
if (B[h[a]] > B[h[b]])
return 1;
else if (B[h[a]] < B[h[b]])
return -1;
else if (A[h[a]] > A[h[b]])
return 1;
else
return -1;
}
}
void swap_h(int a, int b)
{
int f = h[a];
h[a] = h[b];
h[b] = f;
return;
}
void push(int ne)
{
h[l] = ne;
int p = l++;
for (; p > 0; p = (p - 1) / 2)
if (comp_h((p - 1) / 2, p) > 0)
swap_h((p - 1) / 2, p);
return;
}
int pop()
{
swap_h(0, --l);
int p = 0;
for (;;)
{
if (2 * p + 2 < l)
{
if (comp_h(2 * p + 1, 2 * p + 2) > 0)
{
if (comp_h(p, 2 * p + 2) > 0)
swap_h(p, 2 * p + 2);
p = 2 * p + 2;
}
else
{
if (comp_h(p, 2 * p + 1) > 0)
swap_h(p, 2 * p + 1);
p = 2 * p + 1;
}
}
else if (2 * p + 1 < l)
{
if (comp_h(p, 2 * p + 1) > 0)
swap_h(p, 2 * p + 1);
p = 2 * p + 1;
}
else
break;
}
return h[l];
}
int n;
int diff[200005], id[200005];
int cnt1(int d)
{
int min, mid, max;
min = -1;
max = n;
while (max - min > 1)
{
mid = (max + min) / 2;
if (diff[mid] > d)
max = mid;
else
min = mid;
}
return max;
}
int cnt2(int a, int b)
{
int min, mid, max, left, right;
min = -1;
max = n;
while (max - min > 1)
{
mid = (max + min) / 2;
if (B[id[mid]] < b)
min = mid;
else
max = mid;
}
left = max;
min = -1;
max = n;
while (max - min > 1)
{
mid = (max + min) / 2;
if (B[id[mid]] < b)
min = mid;
else if (B[id[mid]] > b)
max = mid;
else if (A[id[mid]] > a)
max = mid;
else
min = mid;
}
right = max;
return right - left;
}
int main()
{
scanf("%d", &n);
int i;
for (i = 0; i < n; i++)
scanf("%d %d", &A[i], &B[i]);
z = 0;
l = 0;
for (i = 0; i < n; i++)
push(A[i]);
for (i = 0; i < n; i++)
diff[i] = pop();
z = 1;
l = 0;
for (i = 0; i < n; i++)
push(i);
for (i = 0; i < n; i++)
id[i] = pop();
int q, x, y;
scanf("%d", &q);
for (i = 0; i < q; i++)
{
scanf("%d %d", &x, &y);
printf("%d\n", cnt1(x) - cnt2(x, y));
}
return 0;
}
pengin_2000