結果
| 問題 | No.3085 Easy  Problems | 
| コンテスト | |
| ユーザー |  pengin_2000 | 
| 提出日時 | 2025-04-04 21:42:06 | 
| 言語 | C (gcc 13.3.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 424 ms / 2,000 ms | 
| コード長 | 2,118 bytes | 
| コンパイル時間 | 713 ms | 
| コンパイル使用メモリ | 26,496 KB | 
| 実行使用メモリ | 7,848 KB | 
| 最終ジャッジ日時 | 2025-04-04 21:42:28 | 
| 合計ジャッジ時間 | 15,678 ms | 
| ジャッジサーバーID (参考情報) | judge6 / judge5 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 2 | 
| other | AC * 31 | 
コンパイルメッセージ
main.c: In function ‘main’:
main.c:123:9: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  123 |         scanf("%d", &n);
      |         ^~~~~~~~~~~~~~~
main.c:126:17: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  126 |                 scanf("%d %d", &A[i], &B[i]);
      |                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~
main.c:140:9: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  140 |         scanf("%d", &q);
      |         ^~~~~~~~~~~~~~~
main.c:143:17: warning: ignoring return value of ‘scanf’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  143 |                 scanf("%d %d", &x, &y);
      |                 ^~~~~~~~~~~~~~~~~~~~~~
            
            ソースコード
#include<stdio.h>
int A[200005], B[200005];
int h[200005], l, z;
int comp_h(int a, int b)
{
	if (z == 0)
	{
		if (h[a] > h[b])
			return 1;
		else
			return -1;
	}
	else
	{
		if (B[h[a]] > B[h[b]])
			return 1;
		else if (B[h[a]] < B[h[b]])
			return -1;
		else if (A[h[a]] > A[h[b]])
			return 1;
		else
			return -1;
	}
}
void swap_h(int a, int b)
{
	int f = h[a];
	h[a] = h[b];
	h[b] = f;
	return;
}
void push(int ne)
{
	h[l] = ne;
	int p = l++;
	for (; p > 0; p = (p - 1) / 2)
		if (comp_h((p - 1) / 2, p) > 0)
			swap_h((p - 1) / 2, p);
	return;
}
int pop()
{
	swap_h(0, --l);
	int p = 0;
	for (;;)
	{
		if (2 * p + 2 < l)
		{
			if (comp_h(2 * p + 1, 2 * p + 2) > 0)
			{
				if (comp_h(p, 2 * p + 2) > 0)
					swap_h(p, 2 * p + 2);
				p = 2 * p + 2;
			}
			else
			{
				if (comp_h(p, 2 * p + 1) > 0)
					swap_h(p, 2 * p + 1);
				p = 2 * p + 1;
			}
		}
		else if (2 * p + 1 < l)
		{
			if (comp_h(p, 2 * p + 1) > 0)
				swap_h(p, 2 * p + 1);
			p = 2 * p + 1;
		}
		else
			break;
	}
	return h[l];
}
int n;
int diff[200005], id[200005];
int cnt1(int d)
{
	int min, mid, max;
	min = -1;
	max = n;
	while (max - min > 1)
	{
		mid = (max + min) / 2;
		if (diff[mid] > d)
			max = mid;
		else
			min = mid;
	}
	return max;
}
int cnt2(int a, int b)
{
	int min, mid, max, left, right;
	min = -1;
	max = n;
	while (max - min > 1)
	{
		mid = (max + min) / 2;
		if (B[id[mid]] < b)
			min = mid;
		else
			max = mid;
	}
	left = max;
	min = -1;
	max = n;
	while (max - min > 1)
	{
		mid = (max + min) / 2;
		if (B[id[mid]] < b)
			min = mid;
		else if (B[id[mid]] > b)
			max = mid;
		else if (A[id[mid]] > a)
			max = mid;
		else
			min = mid;
	}
	right = max;
	return right - left;
}
int main()
{
	scanf("%d", &n);
	int i;
	for (i = 0; i < n; i++)
		scanf("%d %d", &A[i], &B[i]);
	z = 0;
	l = 0;
	for (i = 0; i < n; i++)
		push(A[i]);
	for (i = 0; i < n; i++)
		diff[i] = pop();
	z = 1;
	l = 0;
	for (i = 0; i < n; i++)
		push(i);
	for (i = 0; i < n; i++)
		id[i] = pop();
	int q, x, y;
	scanf("%d", &q);
	for (i = 0; i < q; i++)
	{
		scanf("%d %d", &x, &y);
		printf("%d\n", cnt1(x) - cnt2(x, y));
	}
	return 0;
}
            
            
            
        