結果
問題 |
No.899 γatheree
|
ユーザー |
![]() |
提出日時 | 2025-04-09 20:56:08 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 1,798 bytes |
コンパイル時間 | 571 ms |
コンパイル使用メモリ | 82,444 KB |
実行使用メモリ | 127,960 KB |
最終ジャッジ日時 | 2025-04-09 20:56:39 |
合計ジャッジ時間 | 12,807 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 20 TLE * 1 -- * 2 |
ソースコード
import sys from collections import deque def main(): input = sys.stdin.read data = input().split() ptr = 0 N = int(data[ptr]) ptr += 1 edges = [[] for _ in range(N)] for _ in range(N - 1): u = int(data[ptr]) v = int(data[ptr + 1]) edges[u].append(v) edges[v].append(u) ptr += 2 A = list(map(int, data[ptr:ptr + N])) ptr += N Q = int(data[ptr]) ptr += 1 queries = list(map(int, data[ptr:ptr + Q])) # Precompute adjacency lists adj = [[] for _ in range(N)] for u in range(N): for v in edges[u]: if v not in adj[u]: adj[u].append(v) # Precompute sum_adj sum_adj = [0] * N for u in range(N): sum_adj[u] = sum(A[v] for v in adj[u]) # To avoid recomputing, we'll maintain A and sum_adj dynamically # We'll handle each query by iterating through adjacency lists for x in queries: # Collect all nodes in S(x) s = {x} for v in adj[x]: s.add(v) for u in adj[v]: s.add(u) # Compute sum_total sum_total = 0 cleared = [] for y in s: sum_total += A[y] # Set all y in s (except x) to 0, and update sum_adj for y in s: if y == x: continue if A[y] != 0: val = A[y] A[y] = 0 for u in adj[y]: sum_adj[u] -= val # Set x's A to sum_total and update sum_adj for x's neighbors old_Ax = A[x] A[x] = sum_total delta = sum_total - old_Ax for v in adj[x]: sum_adj[v] += delta print(sum_total) if __name__ == '__main__': main()