結果
| 問題 |
No.1322 Totient Bound
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-15 22:29:54 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 1,805 bytes |
| コンパイル時間 | 276 ms |
| コンパイル使用メモリ | 81,944 KB |
| 実行使用メモリ | 65,772 KB |
| 最終ジャッジ日時 | 2025-04-15 22:31:58 |
| 合計ジャッジ時間 | 7,411 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 10 TLE * 1 -- * 25 |
ソースコード
def is_prime(n):
if n < 2:
return False
for p in [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]:
if n % p == 0:
return n == p
d = n - 1
s = 0
while d % 2 == 0:
d //= 2
s += 1
for a in [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]:
if a >= n:
continue
x = pow(a, d, n)
if x == 1 or x == n - 1:
continue
for _ in range(s - 1):
x = pow(x, 2, n)
if x == n - 1:
break
else:
return False
return True
def solve(N):
if N == 0:
return 1 # Only x=1
count = 0
stack = [(1, 1, 0)] # (current_x, current_phi, last_prime)
while stack:
x, phi, last_p = stack.pop()
if x != 1:
count += 1
K = N // phi
p = last_p + 1
max_p = K + 1
while p <= max_p:
if is_prime(p):
if (p - 1) > K:
p += 1
continue
max_e = 0
current_contribution = 1
for e in range(1, 65): # e starts from 1, up to 2^64
if e == 1:
current_contribution = (p - 1)
else:
current_contribution *= p
if phi * current_contribution > N:
break
max_e = e
if max_e >= 1:
for e in range(1, max_e + 1):
new_x = x * (p ** e)
new_phi = phi * (p - 1) * (p ** (e - 1))
stack.append((new_x, new_phi, p))
p += 1
return count + 1 # +1 for x=1
# Read input and output the result
N = int(input())
print(solve(N))
lam6er