結果
| 問題 |
No.2244 Integer Complete
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-16 01:06:46 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 1,945 bytes |
| コンパイル時間 | 279 ms |
| コンパイル使用メモリ | 81,920 KB |
| 実行使用メモリ | 97,276 KB |
| 最終ジャッジ日時 | 2025-04-16 01:08:15 |
| 合計ジャッジ時間 | 4,701 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 19 TLE * 1 -- * 40 |
ソースコード
import math
def main():
import sys
input = sys.stdin.read().split()
ptr = 0
N, M = int(input[ptr]), int(input[ptr+1])
ptr += 2
A = list(map(int, input[ptr:ptr+N]))
ptr += N
B = list(map(int, input[ptr:ptr+M]))
ptr += M
# Generate x_intervals and y_intervals
x_intervals = []
for a in A:
start = a * a
end = (a + 1) * (a + 1) - 1
x_intervals.append((start, end))
y_intervals = []
for b in B:
start = b * b
end = (b + 1) * (b + 1) - 1
y_intervals.append((start, end))
# Check if 1 is covered
has_A1 = any(a == 1 for a in A)
has_B1 = any(b == 1 for b in B)
if not (has_A1 and has_B1):
print(1)
return
# Function to check if a number is in any of the intervals
def is_in_intervals(x, intervals):
left = 0
right = len(intervals) - 1
while left <= right:
mid = (left + right) // 2
start, end = intervals[mid]
if start > x:
right = mid - 1
else:
if x <= end:
return True
else:
left = mid + 1
return False
k = 2
while True:
divisors = set()
for i in range(1, int(math.isqrt(k)) + 1):
if k % i == 0:
divisors.add(i)
divisors.add(k // i)
covered = False
for d in divisors:
# Check d in x and k/d in y
if is_in_intervals(d, x_intervals) and is_in_intervals(k // d, y_intervals):
covered = True
break
# Check d in y and k/d in x
if is_in_intervals(d, y_intervals) and is_in_intervals(k // d, x_intervals):
covered = True
break
if not covered:
print(k)
return
k += 1
if __name__ == '__main__':
main()
lam6er