結果
| 問題 |
No.1611 Minimum Multiple with Double Divisors
|
| コンテスト | |
| ユーザー |
lam6er
|
| 提出日時 | 2025-04-16 16:47:41 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,224 bytes |
| コンパイル時間 | 329 ms |
| コンパイル使用メモリ | 81,924 KB |
| 実行使用メモリ | 144,268 KB |
| 最終ジャッジ日時 | 2025-04-16 16:50:30 |
| 合計ジャッジ時間 | 12,355 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | -- * 2 |
| other | AC * 1 WA * 10 TLE * 1 -- * 25 |
ソースコード
import sys
import math
def sieve(n):
sieve = [True] * (n + 1)
sieve[0] = sieve[1] = False
for i in range(2, int(math.sqrt(n)) + 1):
if sieve[i]:
sieve[i*i::i] = [False] * len(sieve[i*i::i])
primes = [i for i, is_p in enumerate(sieve) if is_p]
return primes
sieve_primes = sieve(10**6)
def is_prime(n):
if n < 2:
return False
for p in [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]:
if n % p == 0:
return n == p
d = n - 1
s = 0
while d % 2 == 0:
d //= 2
s += 1
for a in [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]:
if a >= n:
continue
x = pow(a, d, n)
if x == 1 or x == n - 1:
continue
for _ in range(s - 1):
x = pow(x, 2, n)
if x == n - 1:
break
else:
return False
return True
def factorize(x, primes):
factors = {}
for p in primes:
if p * p > x:
break
while x % p == 0:
factors[p] = factors.get(p, 0) + 1
x //= p
if x > 1:
if is_prime(x):
factors[x] = 1
else:
i = 2
while i * i <= x:
while x % i == 0:
factors[i] = factors.get(i, 0) + 1
x //= i
i += 1
if x > 1:
factors[x] = 1
return factors
def find_min_p(S, primes):
for p in primes:
if p not in S:
return p
candidate = 2
while True:
if candidate not in S and is_prime(candidate):
return candidate
candidate += 1
def main():
input = sys.stdin.read().split()
T = int(input[0])
cases = list(map(int, input[1:T+1]))
for X in cases:
if X == 1:
print(2)
continue
factors = factorize(X, sieve_primes)
S = set(factors.keys())
p = find_min_p(S, sieve_primes)
Y1 = X * p
if factors:
min_y2 = min(p**(a+1) for p, a in factors.items())
Y2 = X * min_y2
print(min(Y1, Y2))
else:
print(Y1)
if __name__ == "__main__":
main()
lam6er