結果
| 問題 |
No.2293 無向辺 2-SAT
|
| コンテスト | |
| ユーザー |
mkawa2
|
| 提出日時 | 2025-04-24 14:35:39 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 446 ms / 4,000 ms |
| コード長 | 2,754 bytes |
| コンパイル時間 | 524 ms |
| コンパイル使用メモリ | 82,320 KB |
| 実行使用メモリ | 97,216 KB |
| 最終ジャッジ日時 | 2025-04-24 14:36:09 |
| 合計ジャッジ時間 | 26,773 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 53 |
ソースコード
import sys
# sys.setrecursionlimit(200005)
# sys.set_int_max_str_digits(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
# inf = -1-(-1 << 31)
inf = -1-(-1 << 62)
# md = 10**9+7
md = 998244353
class UnionFind:
def __init__(self, n, op, inv, e=0):
self._tree = [-1]*n
self._weight = [e]*n
self._op = op
self._inv = inv
self._e = e
self.cnt = n
self.log = set()
def root(self, u):
stack = []
while self._tree[u] >= 0:
stack.append(u)
u = self._tree[u]
pre = self._e
while stack:
v = stack.pop()
self._tree[v] = u
self._weight[v] = self._op(self._weight[v], pre)
pre = self._weight[v]
return u
def same(self, u, v):
return self.root(u) == self.root(v)
# w(u)+d=w(v)
# 成功:1 済み:0 矛盾:-1 を返す
def merge(self, u, v, d):
ru, rv = self.root(u), self.root(v)
if ru == rv: return -1*(self._op(self._weight[u], d) != self._weight[v])
self.log.add(u)
self.log.add(v)
if self._tree[ru] > self._tree[rv]: ru, rv, u, v, d = rv, ru, v, u, self._inv(d)
self._tree[ru] += self._tree[rv]
self._tree[rv] = ru
self._weight[rv] = self._op(self._op(self._weight[u], d), self._inv(self._weight[v]))
self.cnt -= 1
return 1
# size of connected component
def size(self, u):
return -self._tree[self.root(u)]
def dist(self, u, v):
ru, rv = self.root(u), self.root(v)
if ru != rv: return None
return self._op(self._weight[v], self._inv(self._weight[u]))
def back(self):
for u in self.log:
self._tree[u] = -1
self._weight[u] = self._e
self.cnt = len(self._tree)
self.log = set()
pw = [1]
for _ in range(200005): pw.append(pw[-1]*2%md)
n, q = LI()
uf = UnionFind(n, lambda a, b: a ^ b, lambda a: a)
ng = 0
for _ in range(q):
t, *uv = LI()
if t == 3:
uf.back()
ng = 0
elif ng == 0:
u, v = uv
if uf.merge(u-1, v-1, t-1) == -1: ng = 1
print(0 if ng else pw[uf.cnt])
mkawa2