結果

問題 No.3126 Dual Query Problem
ユーザー dadas
提出日時 2025-04-25 21:31:58
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 147 ms / 2,000 ms
コード長 2,931 bytes
コンパイル時間 1,859 ms
コンパイル使用メモリ 207,068 KB
実行使用メモリ 15,232 KB
最終ジャッジ日時 2025-06-20 02:40:07
合計ジャッジ時間 10,733 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 33
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
//	mt19937 engine((unsigned ll)time(NULL));
//	uniform_int_distribution<ll> distribution(0, (ll)1e18);
//	auto generator = bind(distribution, engine);
//	ll x = generator();
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;
// #define ordered_set tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update>
// #define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag,tree_order_statistics_node_update>
using namespace std;
void _main();
int main() {
	cin.tie(0);
	ios::sync_with_stdio(false);
	_main();
	return 0;
}
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using vi = std::vector<int>;
using vvi = std::vector<vi>;
using vl = std::vector<ll>;
using vii = std::vector<pair<int, int> >;
using vvl = std::vector<vl>;
using vll = std::vector<pair<ll , ll> >;
using vd = std::vector<double>;
using vvd = std::vector<vd>;
using vs = std::vector<std::string>;
using vvs = std::vector<vs>;
using vb = std::vector<bool>;
using vvb = std::vector<vb>;
using vc = std::vector<char>;
using vvc = std::vector<vc>;
using pii = std::pair<int, int>;
using pll = std::pair<ll, ll>;
using piil = std::pair<pair<int, int>, ll>;
using mii = std::map<int, int>;
using mll = std::map<ll, ll>;
using pql = std::priority_queue<ll>;
using pqi = std::priority_queue<int>;
using pqiil = std::priority_queue<pair<pair<int, int>, ll> >;
using pqii = std::priority_queue<pair<int, int> >;

#define pb push_back
#define ps push
#define eb emplace_back
#define is insert
#define er erase
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define sf(i) sizeof(i)
#define endl "\n"
#define all(v) (v).begin(), (v).end()
#define rep(i, L, R) for(ll i = L;i<=R;i++)
#define pcis precision
#define sz(a) ((ll) a.size())

template<typename T>
struct infinity {
	static constexpr T max=std::numeric_limits<T>::max();
	static constexpr T min=std::numeric_limits<T>::min();
	static constexpr T value=std::numeric_limits<T>::max()/2;
	static constexpr T mvalue=std::numeric_limits<T>::min()/2;
};
template<typename T>constexpr T INF=infinity<T>::value;
constexpr ll lINF=INF<ll>;
constexpr int iINF = INF<int>;
constexpr ld PI = 3.1415926535897932384626;



void _main() {

	ll N, Q;
	cin >> N >> Q;
	ll X[N+1];
	memset(X, 0, sf(X));
	rep(i,1,N) cin >> X[i];
	set<ll> se;
	rep(i,1,N) se.is(X[i]);
	if (se.size() + N > Q) {
		cout << "No" << endl;
		return;
	}
	
	cout << "Yes" << endl; 

	map<ll, ll> mp;
	ll cnt = 0;
	rep(i,1,N) {
		if (mp[X[i]] != 0) {
			cout << 2 << " " << mp[X[i]] << endl;
			cnt+=1;
			continue;
		}
		cout << 1 << " " << i << " " << X[i] << endl;
		mp[X[i]] = i;
		cout << 2 << " " << mp[X[i]] << endl;
		cnt+=2;
	}
	
	rep(i, cnt+1, Q) cout << "1 1 1" << endl;
}
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