結果
問題 | No.142 単なる配列の操作に関する実装問題 |
ユーザー | shimomire |
提出日時 | 2015-02-02 02:06:29 |
言語 | C++11 (gcc 11.4.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 6,651 bytes |
コンパイル時間 | 2,540 ms |
コンパイル使用メモリ | 119,300 KB |
実行使用メモリ | 23,364 KB |
最終ジャッジ日時 | 2024-06-23 06:22:10 |
合計ジャッジ時間 | 6,984 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | WA | - |
testcase_01 | WA | - |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
ソースコード
#include <cassert>// c #include <iostream>// io #include <iomanip> #include <fstream> #include <sstream> #include <vector>// container #include <map> #include <set> #include <queue> #include <bitset> #include <stack> #include <algorithm>// other #include <complex> #include <numeric> #include <functional> #include <random> #include <regex> using namespace std; typedef long long ll; typedef unsigned long long ull; #define ALL(c) (begin(c)),(end(c)) #define REP(i,n) FOR(i,0,n) #define REPr(i,n) FORr(i,0,n) #define FOR(i,l,r) for(int i=(int)(l);i<(int)(r);++i) #define FORr(i,l,r) for(int i=(int)(r)-1;i>=(int)(l);--i) #define EACH(it,o) for(auto it = (o).begin(); it != (o).end(); ++it) #define IN(l,v,r) ((l)<=(v) && (v)<(r)) #define UNIQUE(v) v.erase(unique(ALL(v)),v.end()) //debug #define DUMP(x) cerr << #x << " = " << (x) #define LINE() cerr<< " (L" << __LINE__ << ")" class range { private: struct Iter{ int v; int operator*(){return v;} bool operator!=(Iter& itr) {return v < itr.v;} void operator++() {++v;} }; Iter i, n; public: range(int n) : i({0}), n({n}) {} range(int i, int n) : i({i}), n({n}) {} Iter& begin() {return i;} Iter& end() {return n;} }; //input template<typename T1,typename T2> istream& operator >> (istream& is,pair<T1,T2>& p){return is>>p.first>>p.second;} template<typename T1> istream& operator >> (istream& is,tuple<T1>& t){return is >> get<0>(t);} template<typename T1,typename T2> istream& operator >> (istream& is,tuple<T1,T2>& t){return is >> get<0>(t) >> get<1>(t);} template<typename T1,typename T2,typename T3> istream& operator >> (istream& is,tuple<T1,T2,T3>& t){return is >>get<0>(t)>>get<1>(t)>>get<2>(t);} template<typename T1,typename T2,typename T3,typename T4> istream& operator >> (istream& is,tuple<T1,T2,T3,T4>& t){return is >> get<0>(t)>>get<1>(t)>>get<2>(t)>>get<3>(t);} template<typename T1,typename T2,typename T3,typename T4,typename T5> istream& operator >> (istream& is, const tuple<T1,T2,T3,T4,T5>& t){return is >> get<0>(t) >> get<1>(t) >> get<2>(t) >> get<3>(t) >> get<4>(t);} template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6> istream& operator >> (istream& is, const tuple<T1,T2,T3,T4,T5,T6>& t){return is >> get<0>(t) >> get<1>(t) >> get<2>(t) >> get<3>(t) >> get<4>(t) >> get<5>(t);} template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6,typename T7> istream& operator >> (istream& is, const tuple<T1,T2,T3,T4,T5,T6,T7>& t){return is >> get<0>(t) >> get<1>(t) >> get<2>(t) >> get<3>(t) >> get<4>(t) >> get<5>(t) >> get<6>(t);} template<typename T> istream& operator >> (istream& is,vector<T>& as){for(int i:range(as.size()))is >>as[i];return is;} //output template<typename T> ostream& operator << (ostream& os, const set<T>& ss){for(auto a:ss){if(a!=ss.begin())os<<" "; os<<a;}return os;} template<typename T1,typename T2> ostream& operator << (ostream& os, const pair<T1,T2>& p){os<<p.first<<" "<<p.second;return os;} template<typename K,typename V> ostream& operator << (ostream& os, const map<K,V>& m){bool isF=true;for(auto& p:m){if(!isF)os<<endl;os<<p;isF=false;}return os;} template<typename T1> ostream& operator << (ostream& os, const tuple<T1>& t){return os << get<0>(t);} template<typename T1,typename T2> ostream& operator << (ostream& os, const tuple<T1,T2>& t){return os << get<0>(t)<<" "<<get<1>(t);} template<typename T1,typename T2,typename T3> ostream& operator << (ostream& os, const tuple<T1,T2,T3>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t);} template<typename T1,typename T2,typename T3,typename T4> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t);} template<typename T1,typename T2,typename T3,typename T4,typename T5> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t);} template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5,T6>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t)<<" "<<get<5>(t);} template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6,typename T7> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5,T6,T7>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t)<<" "<<get<5>(t)<<" "<<get<6>(t);} template<typename T> ostream& operator << (ostream& os, const vector<T>& as){for(int i:range(as.size())){if(i!=0)os<<" "; os<<as[i];}return os;} template<typename T> ostream& operator << (ostream& os, const vector<vector<T>>& as){for(int i:range(as.size())){if(i!=0)os<<endl; os<<as[i];}return os;} // values template<typename T> T INF(){assert(false);}; template<> int INF<int>(){return 1<<28;}; template<> ll INF<ll>(){return 1LL<<58;}; template<> double INF<double>(){return 1e16;}; template<> long double INF<long double>(){return 1e16;}; template<class T> T EPS(){assert(false);}; template<> int EPS<int>(){return 1;}; template<> ll EPS<ll>(){return 1LL;}; template<> double EPS<double>(){return 1e-8;}; template<> long double EPS<long double>(){return 1e-8;}; template<typename T,typename U> T pmod(T v,U M){return (v%M+M)%M;} ll gcd_positive(ll a,ll b) { return b == 0 ? a : gcd_positive(b,a%b); } ll gcd(ll a,ll b) { return gcd_positive(abs(a), abs(b)); } ll lcm(ll a,ll b){return a/gcd(a,b)*b;} class Main{ public: void run(){ int N;ll S,X,Y,Z;cin >> N >> S >> X >> Y >> Z; vector<ll> as(N);as[0]=S; for(int i:range(1,N)){ as[i]=(X*as[i-1]+Y)%Z; } REP(i,N)as[i]%=2; int B=60; vector<ll> bs(N/B+3); REP(i,N) bs[i/B]|=as[i]<<(i%B); vector<ll> nbs=bs; int Q;cin >> Q; REP(q,Q){ int s,t,u,v;cin >> s >> t >> u >> v;s--;u--; while(s<t && s%B!=0){ ll b=(bs[s/B]>>(s%B))&1; bs[u/B]^=(b<<(u%B)); s++,u++; } while(s<t && t%B!=0){ t--,v--; ll b=(bs[t/B]>>(t%B))&1; bs[v/B]^=(b<<(v%B)); } for(int b:range(s/B,t/B)){ ll bit1=bs[b] & ((1LL<<(B-u%B))-1); nbs[u/B+(b-s/B)]^=(bit1<<(u%B)); ll bit2=bs[b]>>(B - u%B); nbs[u/B+(b-s/B)+1]^=bit2; } for(int b:range(s/B,t/B)){ bs[u/B+(b-s/B)]=nbs[u/B+(b-s/B)]; bs[u/B+(b-s/B)+1]=nbs[u/B+(b-s/B)+1]; } } REP(i,N)as[i]=(bs[i/B]>>(i%B))&1; string res=""; REP(i,N)res+=as[i]?'O':'E'; cout << res <<endl; } }; int main(){ cout <<fixed<<setprecision(20); cin.tie(0); ios::sync_with_stdio(false); Main().run(); return 0; }