結果
| 問題 |
No.3173 じゃんけんの勝ちの回数
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2025-06-06 22:29:47 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 65 ms / 2,000 ms |
| コード長 | 2,988 bytes |
| コンパイル時間 | 5,146 ms |
| コンパイル使用メモリ | 259,856 KB |
| 実行使用メモリ | 6,272 KB |
| 最終ジャッジ日時 | 2025-06-06 22:29:56 |
| 合計ジャッジ時間 | 7,151 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 33 |
ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int solve(){
vector<int> a(3);
vector<int> b(3);
cin >> a >> b;
const int INF = 1001001001;
int s = 0;
rep(i, 3) s += a[i];
auto solve_min = [&](vector<int> a, vector<int> b){
int res = INF;
auto judge = [&](){
mf_graph<int> graph(8);
rep(j, 3){
graph.add_edge(j, j + 3, INF);
graph.add_edge(j, (j + 2) % 3 + 3, INF);
}
int sv = 6;
int tv = 7;
rep(j, 3){
graph.add_edge(sv, j, a[j]);
graph.add_edge(j + 3, tv, b[j]);
}
return graph.flow(sv, tv);
};
return s - judge();
};
auto solve_max = [&](vector<int> a, vector<int> b){
int res = 0;
res += min(a[0], b[1]);
res += min(a[1], b[2]);
res += min(a[2], b[0]);
return res;
};
cout << solve_min(a, b) << ' ' << solve_max(a, b) << "\n";
return 0;
}
int main(){
int t;
cin >> t;
rep(_, t) solve();
return 0;
}