結果
問題 |
No.298 話の伝達
|
ユーザー |
![]() |
提出日時 | 2025-06-12 14:10:01 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,891 bytes |
コンパイル時間 | 180 ms |
コンパイル使用メモリ | 82,352 KB |
実行使用メモリ | 56,656 KB |
最終ジャッジ日時 | 2025-06-12 14:10:31 |
合計ジャッジ時間 | 1,941 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 10 WA * 11 |
ソースコード
from collections import deque def main(): n, m = map(int, input().split()) adj = [[] for _ in range(n)] # adjacency list for forward edges in_edges = [[] for _ in range(n)] # list of incoming edges (A, C) for each node B for _ in range(m): a, b, c = map(int, input().split()) adj[a].append(b) in_edges[b].append((a, c)) # Find reachable nodes from group 0 using BFS def get_reachable(start): visited = [False] * n q = deque([start]) visited[start] = True while q: u = q.popleft() for v in adj[u]: if not visited[v]: visited[v] = True q.append(v) return [i for i in range(n) if visited[i]] reachable = get_reachable(0) if (n-1) not in reachable: print(0.0) return # Perform topological sort on the reachable nodes def topological_sort(nodes): visited = {node: False for node in nodes} order = [] def dfs(u): if visited[u]: return visited[u] = True for v in adj[u]: if v in visited and not visited[v]: dfs(v) order.append(u) for node in nodes: if not visited[node]: dfs(node) return order[::-1] topo_order = topological_sort(reachable) # Calculate probabilities prob = [0.0] * n prob[0] = 1.0 # initial group for u in topo_order: if u == 0: continue product = 1.0 for (a, c) in in_edges[u]: if a < 0 or a >= n: continue # should not happen as per input constraints product *= (1.0 - prob[a] * (c / 100.0)) prob[u] = 1.0 - product print("{0:.10f}".format(prob[n-1])) if __name__ == "__main__": main()