結果

問題 No.3038 シャッフルの再現
ユーザー gew1fw
提出日時 2025-06-12 14:27:20
言語 PyPy3
(7.3.15)
結果
RE  
実行時間 -
コード長 2,375 bytes
コンパイル時間 475 ms
コンパイル使用メモリ 82,416 KB
実行使用メモリ 68,232 KB
最終ジャッジ日時 2025-06-12 14:27:59
合計ジャッジ時間 2,677 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample RE * 1
other RE * 21
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys
import math

MOD = 10**9 + 7

def factor(n):
    factors = {}
    while n % 2 == 0:
        factors[2] = factors.get(2, 0) + 1
        n = n // 2
    i = 3
    while i * i <= n:
        while n % i == 0:
            factors[i] = factors.get(i, 0) + 1
            n = n // i
        i += 2
    if n > 1:
        factors[n] = 1
    return factors

def generate_divisors(factors_dict):
    divisors = [1]
    for p in sorted(factors_dict.keys()):
        exp = factors_dict[p]
        current_powers = [p**e for e in range(exp + 1)]
        new_divisors = []
        for d in divisors:
            for power in current_powers:
                new_divisors.append(d * power)
        divisors = list(sorted(set(new_divisors)))
    return sorted(divisors)

def fib_pair(n, mod):
    if n == 0:
        return (0, 1)
    a, b = fib_pair(n // 2, mod)
    c = (a * (2 * b - a)) % mod
    d = (a * a + b * b) % mod
    if n % 2 == 0:
        return (c, d)
    else:
        return (d, (c + d) % mod)

def compute_pisano_period(p):
    if p == 2:
        return 3
    if p == 5:
        return 20
    mod5 = p % 5
    if mod5 in (1, 4):
        candidate = p - 1
    else:
        candidate = 2 * (p + 1)
    factors = factor(candidate)
    divisors = generate_divisors(factors)
    for d in sorted(divisors):
        if d == 0:
            continue
        fn, fn1 = fib_pair(d, p)
        if fn == 0 and fn1 == 1:
            return d
    return candidate

def main():
    input = sys.stdin.read().split()
    ptr = 0
    N = int(input[ptr])
    ptr += 1
    factors = []
    for _ in range(N):
        p = int(input[ptr])
        k = int(input[ptr + 1])
        ptr += 2
        factors.append((p, k))
    
    periods = []
    for p, k in factors:
        if p == 2:
            if k == 1:
                pi_pk = 3
            elif k == 2:
                pi_pk = 6
            else:
                pi_pk = 3 * (2 ** (k - 1))
        elif p == 5:
            if k == 1:
                pi_pk = 20
            else:
                pi_pk = 20 * (5 ** (k - 1))
        else:
            pi_p = compute_pisano_period(p)
            pi_pk = pi_p * (p ** (k - 1))
        periods.append(pi_pk)
    
    current_lcm = 1
    for p in periods:
        current_lcm = current_lcm * p // math.gcd(current_lcm, p)
    print(current_lcm % MOD)

if __name__ == "__main__":
    main()
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