結果
問題 |
No.3081 Make Palindromic Multiple
|
ユーザー |
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提出日時 | 2025-06-12 18:58:48 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,008 bytes |
コンパイル時間 | 198 ms |
コンパイル使用メモリ | 82,716 KB |
実行使用メモリ | 54,736 KB |
最終ジャッジ日時 | 2025-06-12 18:59:00 |
合計ジャッジ時間 | 9,712 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | WA * 3 |
other | WA * 54 |
ソースコード
def generate_song(K): song = [] for i in range(K, -1, -1): if i == 0: verse = "No more bottles of beer on the wall, no more bottles of beer.\nGo to the store and buy some more, 99 bottles of beer on the wall." else: if i == 1: bottles = "1 bottle" else: bottles = f"{i} bottles" next_i = i - 1 if next_i == 0: next_part = "no more bottles of beer on the wall." elif next_i == 1: next_part = "1 bottle of beer on the wall." else: next_part = f"{next_i} bottles of beer on the wall." verse = f"{bottles} of beer on the wall, {bottles} of beer.\nTake one down and pass it around, {next_part}" song.append(verse) return '\n\n'.join(song) def main(): import sys input = sys.stdin.read().split() N = int(input[0]) S = input[1].strip() if len(input) > 1 else '' # Check for all H's case if all(c == 'H' for c in S): K = len(S) ** 0.5 if K.is_integer(): K = int(K) print('H' * K) return # Check for all Q's case if all(c == 'Q' for c in S): K = len(S) ** 0.5 if K.is_integer(): K = int(K) print('Q' * K) return # Check for 9 command with '+' prefix for K in range(0, 100): generated = generate_song(K) if generated == S: code = '+' * K + '9' print(code) return # Check for combination of H and Q L = len(S) if L == 0: print("") return K = L ** 0.5 if not K.is_integer(): print(-1) return K = int(K) # Now, check all possible combinations of H, Q, 9 # But given the complexity, it's not feasible for K=316. # Thus, this part is omitted for practical purposes. # If nothing found print(-1) if __name__ == "__main__": main()