結果
| 問題 |
No.298 話の伝達
|
| コンテスト | |
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 19:05:57 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,652 bytes |
| コンパイル時間 | 171 ms |
| コンパイル使用メモリ | 82,572 KB |
| 実行使用メモリ | 56,064 KB |
| 最終ジャッジ日時 | 2025-06-12 19:06:47 |
| 合計ジャッジ時間 | 1,806 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 10 WA * 11 |
ソースコード
import sys
from collections import defaultdict, deque
def main():
N, M = map(int, sys.stdin.readline().split())
edges = defaultdict(list) # Forward edges for BFS/DFS
reverse_edges = defaultdict(list) # Reverse edges for probability calculation
for _ in range(M):
A, B, C = map(int, sys.stdin.readline().split())
edges[A].append(B)
reverse_edges[B].append((A, C))
# Determine all nodes reachable from group 0 using BFS
reachable = set()
queue = deque([0])
reachable.add(0)
while queue:
u = queue.popleft()
for v in edges[u]:
if v not in reachable:
reachable.add(v)
queue.append(v)
# Perform topological sort using DFS on reachable nodes
visited = set()
topo_order = []
def dfs(u):
if u in visited or u not in reachable:
return
visited.add(u)
for v in edges[u]:
dfs(v)
topo_order.append(u)
dfs(0)
topo_order.reverse() # Reverse to get the correct topological order
# Initialize probabilities
prob = [0.0] * N
prob[0] = 1.0 # Group 0 starts with probability 1.0
# Process each node in topological order
for v in topo_order:
if v == 0:
continue # Skip group 0 as its probability is already set
product = 1.0
for (u, c) in reverse_edges[v]:
if u in reachable:
product *= (1.0 - prob[u] * (c / 100))
prob[v] = 1.0 - product
# Output the result with sufficient precision
print("{0:.10f}".format(prob[N-1]))
if __name__ == "__main__":
main()
gew1fw