結果
| 問題 | 
                            No.1928 Make a Binary Tree
                             | 
                    
| コンテスト | |
| ユーザー | 
                             gew1fw
                         | 
                    
| 提出日時 | 2025-06-12 20:15:05 | 
| 言語 | PyPy3  (7.3.15)  | 
                    
| 結果 | 
                             
                                WA
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 1,736 bytes | 
| コンパイル時間 | 213 ms | 
| コンパイル使用メモリ | 82,688 KB | 
| 実行使用メモリ | 174,660 KB | 
| 最終ジャッジ日時 | 2025-06-12 20:18:09 | 
| 合計ジャッジ時間 | 22,657 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge1 / judge4 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 24 WA * 33 | 
ソースコード
import sys
from collections import deque
def main():
    sys.setrecursionlimit(1 << 25)
    n = int(sys.stdin.readline())
    adj = [[] for _ in range(n+1)]
    for _ in range(n-1):
        x, y = map(int, sys.stdin.readline().split())
        adj[x].append(y)
        adj[y].append(x)
    
    # Build the tree with parent and children
    parent = [0] * (n + 1)
    children = [[] for _ in range(n + 1)]
    visited = [False] * (n + 1)
    q = deque([1])
    visited[1] = True
    while q:
        u = q.popleft()
        for v in adj[u]:
            if not visited[v] and v != parent[u]:
                parent[v] = u
                children[u].append(v)
                visited[v] = True
                q.append(v)
    
    # Iterative post-order traversal
    stack = [(1, False)]
    post_order = []
    while stack:
        node, processed = stack.pop()
        if processed:
            post_order.append(node)
        else:
            stack.append((node, True))
            # Push children in reverse order to process them in order
            for child in reversed(children[node]):
                stack.append((child, False))
    
    candidates = {}
    for node in post_order:
        merged = []
        for child in children[node]:
            merged.extend(candidates[child])
        merged.sort(reverse=True)
        sum_size = sum(merged[:2]) if len(merged) >= 2 else sum(merged)
        size = sum_size + 1
        new_candidates = [size]
        if len(merged) > 2:
            new_candidates.extend(merged[2:])
        # Truncate to at most two elements
        new_candidates = new_candidates[:2]
        candidates[node] = new_candidates
    
    print(candidates[1][0])
if __name__ == '__main__':
    main()
            
            
            
        
            
gew1fw