結果
| 問題 | No.1611 Minimum Multiple with Double Divisors | 
| コンテスト | |
| ユーザー |  gew1fw | 
| 提出日時 | 2025-06-12 21:33:16 | 
| 言語 | PyPy3 (7.3.15) | 
| 結果 | 
                                WA
                                 
                             | 
| 実行時間 | - | 
| コード長 | 1,832 bytes | 
| コンパイル時間 | 373 ms | 
| コンパイル使用メモリ | 82,036 KB | 
| 実行使用メモリ | 99,280 KB | 
| 最終ジャッジ日時 | 2025-06-12 21:34:24 | 
| 合計ジャッジ時間 | 8,581 ms | 
| ジャッジサーバーID (参考情報) | judge4 / judge5 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | -- * 2 | 
| other | AC * 1 WA * 10 TLE * 1 -- * 25 | 
ソースコード
import sys
def factorize(x):
    factors = {}
    while x % 2 == 0:
        factors[2] = factors.get(2, 0) + 1
        x = x // 2
    i = 3
    while i * i <= x:
        while x % i == 0:
            factors[i] = factors.get(i, 0) + 1
            x = x // i
        i += 2
    if x > 1:
        factors[x] = 1
    return factors
def is_prime(n):
    if n < 2:
        return False
    if n % 2 == 0:
        return n == 2
    max_div = int(n ** 0.5) + 1
    for i in range(3, max_div, 2):
        if n % i == 0:
            return False
    return True
def find_min_q(factors):
    primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293]
    for p in primes:
        if p not in factors:
            return p
    next_p = primes[-1] + 2
    while True:
        if is_prime(next_p) and next_p not in factors:
            return next_p
        next_p += 2
def main():
    input = sys.stdin.read().split()
    T = int(input[0])
    for i in range(1, T + 1):
        X = int(input[i])
        if X == 0:
            print(0)
            continue
        factors = factorize(X)
        case2_candidates = []
        for p, e in factors.items():
            if (e + 1) % 2 == 0:
                power = e + 1
                y_i = X * (p ** power)
                case2_candidates.append(y_i)
        min_case2 = None
        if case2_candidates:
            min_case2 = min(case2_candidates)
        q = find_min_q(factors)
        y_j = X * q
        if case2_candidates:
            y = min(min_case2, y_j)
        else:
            y = y_j
        print(y)
if __name__ == "__main__":
    main()
            
            
            
        