結果

問題 No.3204 Permuted Integer
ユーザー 👑 binap
提出日時 2025-07-18 22:04:16
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 285 ms / 2,000 ms
コード長 2,723 bytes
コンパイル時間 4,127 ms
コンパイル使用メモリ 259,652 KB
実行使用メモリ 7,716 KB
最終ジャッジ日時 2025-07-18 23:39:43
合計ジャッジ時間 9,567 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 26
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef pair<int, int> P;

template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

int main(){
	map<vector<int>, int> memo;
	
	auto f = [&](int x){
		vector<int> res(10);
		while(x > 0){
			res[x % 10]++;
			x /= 10;
		}
		return res;
	};
	
	for(int x = 1; x * x <= 1000000000; x++){
		vector<int> cnt = f(x * x);
		if(memo.find(cnt) == memo.end()) memo[cnt] = x * x;
	}
	int t;
	cin >> t;
	
	const int INF = 1001001001;
	
	rep(_, t){
		int n;
		cin >> n;
		vector<int> cnt = f(n);
		int ans = INF;
		while(cnt[0] >= 0){
			if(memo.find(cnt) != memo.end()){
				chmin(ans, memo[cnt]);
			}
			cnt[0]--;
		}
		if(ans == INF) cout << "-1\n";
		else cout << ans << "\n";
	}
	return 0;
}
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