結果
問題 |
No.3204 Permuted Integer
|
ユーザー |
👑 |
提出日時 | 2025-07-18 22:04:16 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 285 ms / 2,000 ms |
コード長 | 2,723 bytes |
コンパイル時間 | 4,127 ms |
コンパイル使用メモリ | 259,652 KB |
実行使用メモリ | 7,716 KB |
最終ジャッジ日時 | 2025-07-18 23:39:43 |
合計ジャッジ時間 | 9,567 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 26 |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef pair<int, int> P; template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;} template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} int main(){ map<vector<int>, int> memo; auto f = [&](int x){ vector<int> res(10); while(x > 0){ res[x % 10]++; x /= 10; } return res; }; for(int x = 1; x * x <= 1000000000; x++){ vector<int> cnt = f(x * x); if(memo.find(cnt) == memo.end()) memo[cnt] = x * x; } int t; cin >> t; const int INF = 1001001001; rep(_, t){ int n; cin >> n; vector<int> cnt = f(n); int ans = INF; while(cnt[0] >= 0){ if(memo.find(cnt) != memo.end()){ chmin(ans, memo[cnt]); } cnt[0]--; } if(ans == INF) cout << "-1\n"; else cout << ans << "\n"; } return 0; }