結果
問題 |
No.3280 Black-Tailed Gull vs Monster
|
ユーザー |
|
提出日時 | 2025-09-26 21:27:09 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 150 ms / 2,000 ms |
コード長 | 1,774 bytes |
コンパイル時間 | 223 ms |
コンパイル使用メモリ | 82,576 KB |
実行使用メモリ | 92,756 KB |
最終ジャッジ日時 | 2025-09-26 21:27:19 |
合計ジャッジ時間 | 4,923 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 40 |
ソースコード
# input import sys input = sys.stdin.readline II = lambda : int(input()) MI = lambda : map(int, input().split()) LI = lambda : [int(a) for a in input().split()] SI = lambda : input().rstrip() LLI = lambda n : [[int(a) for a in input().split()] for _ in range(n)] LSI = lambda n : [input().rstrip() for _ in range(n)] MI_1 = lambda : map(lambda x:int(x)-1, input().split()) LI_1 = lambda : [int(a)-1 for a in input().split()] mod = 998244353 inf = 1001001001001001001 ordalp = lambda s : ord(s)-65 if s.isupper() else ord(s)-97 ordallalp = lambda s : ord(s)-39 if s.isupper() else ord(s)-97 yes = lambda : print("Yes") no = lambda : print("No") yn = lambda flag : print("Yes" if flag else "No") prinf = lambda ans : print(ans if ans < 1000001001001001001 else -1) alplow = "abcdefghijklmnopqrstuvwxyz" alpup = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" alpall = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" URDL = {'U':(-1,0), 'R':(0,1), 'D':(1,0), 'L':(0,-1)} DIR_4 = [[-1,0],[0,1],[1,0],[0,-1]] DIR_8 = [[-1,0],[-1,1],[0,1],[1,1],[1,0],[1,-1],[0,-1],[-1,-1]] DIR_BISHOP = [[-1,1],[1,1],[1,-1],[-1,-1]] prime60 = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59] sys.set_int_max_str_digits(0) # sys.setrecursionlimit(10**6) # import pypyjit # pypyjit.set_param('max_unroll_recursion=-1') from collections import defaultdict,deque from heapq import heappop,heappush from bisect import bisect_left,bisect_right DD = defaultdict BSL = bisect_left BSR = bisect_right n, x, q = MI() ans = 0 for i in range(q): m = II() f = LI() f.sort() c = 0 for i in range(m): if f[i] == x: c = 1 if c: ans += 1 continue for i in range(m-1): if f[i] == f[i+1]: ans += 1/2 break print(ans)