結果
| 問題 |
No.3332 Consecutive Power Sum (Small)
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-10-20 23:40:40 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 3,077 bytes |
| コンパイル時間 | 165 ms |
| コンパイル使用メモリ | 82,580 KB |
| 実行使用メモリ | 85,156 KB |
| 最終ジャッジ日時 | 2025-11-02 21:13:55 |
| 合計ジャッジ時間 | 4,267 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | WA * 2 |
| other | WA * 8 TLE * 1 -- * 43 |
ソースコード
#! /usr/bin/env pypy
def test_miller_rabin(n: int, bases: list):
nn = n - 1
e = (nn & -nn).bit_length() - 1
o = n >> e
# assert n == (o << e | 1)
for b in bases:
x = pow(b, o, n)
if x == 1:
continue
for _ in range(e):
y = pow(x, 2, n)
if y == 1:
if x == n - 1:
break
else:
# nontrivial sqrt(1) found
return False
x = y
else:
return False
return True
def is_prime(n: int):
if n < 2:
return False
for p in [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]:
if n == p:
return True
if n % p == 0:
return False
if n < 41**2:
return True
if n < 2047:
return test_miller_rabin(n, [2])
if n < 90_80191:
return test_miller_rabin(n, [31, 73])
if n < 47591_23141:
return test_miller_rabin(n, [2, 7, 61])
if n < 112_20046_69633:
return test_miller_rabin(n, [2, 13, 23, 16_62803])
if n < 3_77057_95821_54547:
return test_miller_rabin(n, [2, 8_80937, 25_70940, 6103_86380, 41307_85767])
return test_miller_rabin(n, [2, 325, 9375, 28178, 450775, 9780504, 17952_65022])
from math import gcd
def factorize(n: int):
assert n >= 1
if n == 1:
return []
if is_prime(n):
return [n]
ans = []
for p in [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]:
while n % p == 0:
n //= p
ans.append(p)
def dfs(nn: int):
if nn == 1:
return
if is_prime(nn):
ans.append(nn)
return
factor_round = 1 << nn.bit_length() // 8
def find_factor():
x0 = 0
def f(x):
return (x * x + 1) % nn
while True:
x0 += 1
x, y = x0, f(x0)
d = 1
checkpoint = x, y
while d == 1:
combined = 1
for _ in range(factor_round):
# Floyd's
x, y = f(x), f(f(y))
combined = combined * abs(x - y) % nn
d = gcd(combined, nn)
if d == 1:
# この round では見つからなかった
checkpoint = x, y
elif d != nn:
# 非自明な約数
return d
# else: d == nn: maybe found, break
# 1つずつ進める
x, y = checkpoint
d = 1
while d == 1:
x, y = f(x), f(f(y))
d = gcd(abs(x - y), nn)
if d != 1 and d != nn:
return d
d = find_factor()
dfs(d)
dfs(nn // d)
dfs(n)
return ans
def solve():
n = int(input())
factorize(n)
if __name__ == "__main__":
solve()